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anastassius [24]
3 years ago
5

Explain me the inertia of rest ?

Physics
1 answer:
sergejj [24]3 years ago
3 0






Hi Pupil Here is Your Answer ::





➡➡➡➡➡➡➡➡➡➡➡➡➡





The tendency of a body to oppose any change in its state of rest is known as inertia of rest.


Example :


1 ) A person standing in a bus Falls backward when the bus suddenly starts moving forward.




Reason》When the bus Moves, the lower part of his party begins to move along with the bus by the upper part of his body continues to remain at rest due to inertia of rest.


That is why, a person Falls backward when the bus suddenly starts.




⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅⬅




Hope this helps . . . . . .
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Answer:

Neglecting any frictional losses, the average power delivered by the car's engine is 10565 W

Explanation:

The energy conservation law indicates that the energy must be the same at the bottom of the hill and at the top of the hill.  

The energy at the bottom is only the Kinect energy (K_1) of the car in motion, but in the top, the energy is the sum of its Kinect energy (K_2), potential energy (P) and the work (W) done by the engine.

K_1 = K_2 + P + W

then, the work done by the engine is:

W = K_1 - K_2 - P

The formulas for the Kinetic and potential energy are:  

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Using the formulas:

W=\frac{1}{2}mV_1^2-\frac{1}{2}mV_2^2-mgh

Replacing the values:

W=\frac{1}{2}(1600Kg)(27m/s)^2-\frac{1}{2}(1600Kg)(14m/s)^2-(1600Kg)(9.8m/s^2)(135m)\\W=-1690400 J

The negative of this value indicates the direction of the work done, but for the problem, you only care about the magnitude, so the power is W=1690400 J. Now, the power is equal to work/time so you need to find the time the car took to get to the top of the hill.

The average speed of the car is (27+14)/2=20m/s, and t=d/v so the time is:

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the power delivered by the car's engine was:

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as it is given that it covers a total distance 1 * 10^2 m

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