1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
evablogger [386]
3 years ago
6

A tow truck drags a stalled car along a road. The chain makes an angle of 30° with the road and the tension in the chain is 1000

N. How much work is done by the truck in pulling the car 1 km? (Round your answer to the nearest ten thousand.) joules
Physics
1 answer:
statuscvo [17]3 years ago
6 0

To develop this problem it is necessary to apply the work theorem. This tells us that the energy on a body is equivalent to the product between the Force applied on it and the distance traveled. The vector product of these measures can be expressed as

W = \vec{F}\times \vec{x}

And its magnitude is equivalent to

W = Fx cos\theta

Where \theta is the angle formed between the applied force and the line of displacement of the body.

Our values are given as,

\theta = 30\°

F= 1500N

x = 1000m

Applying this value and replacing we have,

W = Fxcos\theta

W = (1500)(1000)cos(30)

W = 1.299*10^6J

Therefore the work done by the truck is 1.299 Mega Jules

You might be interested in
Consider this statement: Air is matter. Which facts best support the statement?
lyudmila [28]
A. Balloons can be filled with air.
C. Air has mass.
7 0
3 years ago
Read 2 more answers
A car is up on a hydraulic lift at a garage. The wheels are free to rotate, and the drive wheels are rotating with a constant an
masya89 [10]

Answer:

Explanation:

Given

Wheels are rotating with constant angular velocity let say \omega

Presence of constant angular velocity show that there is no angular acceleration thus there is no tangential acceleration.

But any particle on the rim will experience a constant acceleration towards center called centripetal acceleration.

(a) yes, there will be tangential velocity which is given by

v=r\cdot \omega

where r=radial distance from center

(b)tangential acceleration

there would be no tangential acceleration as velocity is constant

(c)centripetal acceleration

Yes, there will be centripetal acceleration given by

a_c=\omega ^2\times r

                                   

7 0
3 years ago
An inexperienced researcher runs an experiment and sets his alpha level at .40 because he can't wait to get his firstsignificant
GuDViN [60]

A potential problem is that you are willing to accept a <u>5% </u>chance of being wrong if you reject the null hypothesis.

The significance level is the probability of rejecting the null hypothesis if it is true. For example, a significance level of 0.05 indicates a 5% risk of concluding that there is a difference when there is actually no difference. Rejecting the true null hypothesis results in a Type I error.

The smaller the value of α the more difficult it is to reject the null hypothesis. Therefore, choosing a low value for α can reduce the likelihood of Type I errors. The result here is that if the null hypothesis is false, it may be more difficult to reject using a lower value for α. The alpha value or statistical significance threshold is arbitrary. Which value to use depends on your field of study.

Learn more about The potential problems here:-brainly.com/question/21836542

#SPJ4

4 0
1 year ago
Mr. hitch taught us about sedimentary, metamorphic, and igneous rocks. he described how they were formed, what they contain, and
Tems11 [23]
Mr. Hitch taught us about sedimentary, metamorphic, and igneous rocks. He described how they were formed, what they contain, and showed us samples of each. He is a good geologist. 

The missing word and answer is: geologist.
3 0
3 years ago
A 2,700-kg truck runs into the rear of a 1,000-kg car that was stationary. The truck and car are locked together after the colli
Leto [7]

Answer:

6200 J

Explanation:

Momentum is conserved.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

The car is initially stationary.  The truck and car stick together after the collision, so they have the same final velocity.  Therefore:

m₁ u₁ = (m₁ + m₂) v

Solving for the truck's initial velocity:

(2700 kg) u = (2700 kg + 1000 kg) (3 m/s)

u = 4.11 m/s

The change in kinetic energy is therefore:

ΔKE = ½ (m₁ + m₂) v² − ½ m₁ u²

ΔKE = ½ (2700 kg + 1000 kg) (3 m/s)² − ½ (2700 kg) (4.11 m/s)²

ΔKE = -6200 J

6200 J of kinetic energy is "lost".

3 0
3 years ago
Other questions:
  • Graphs help you see..
    9·1 answer
  • A force acts on an object and moves it a certain distance
    6·1 answer
  • Africa has _____ countries.
    6·2 answers
  • The rope of the length 6 m is fixed to a vertical wall in the horizontal x-direction. We send one transverse pulse on a rope in
    6·1 answer
  • Compare and Contrast refracting and reflecting microscopes?
    9·1 answer
  • Which statement about subatomic particles is NOT true?
    5·1 answer
  • A high-mass star has more "fuel" than a low-mass star. which lives longer? why?
    11·1 answer
  • When the course deviation indicator (CDI) needle is centered during an omnireceiver check using a VOR test signal (VOT), the omn
    11·1 answer
  • Which two quantities can be expressed using the same units?
    6·1 answer
  • When you think about and describe the characteristics of a giraffe, what type of model are you using?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!