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IRISSAK [1]
3 years ago
5

This element is a liquid at room temperature. (A) Hg (B) Th (C) Na (D) Cl (E) Co

Chemistry
2 answers:
gulaghasi [49]3 years ago
7 0
A) Hg, or Mercury, is a liquid at room temperature. Hope this helps!!
mihalych1998 [28]3 years ago
7 0
This element is also unique since it is in the row of metalloids, it is;
A. Hg (Mercury)
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To melt the ice on your driveway, you can use two moles of rock salt (NaCl) or two moles of calcium chloride (CaCl2). Which solu
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I know it would be calcium chloride, not sure why. Maybe someone could answer that part.
3 0
3 years ago
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Which layer contains almost 90% of the atmosphere's total mass?
Afina-wow [57]
The answer is the troposphere

4 0
3 years ago
Help on 2 and 3 due tomorrow pls help
Luda [366]

Answer:

2

b= they are grouped differently, but all the atoms are still there.

4 0
2 years ago
1 Na2CO3(aq) + 1 CaCl2(aq) → 1 CaCO3(s) + 2 NaCl(aq) 4. Use the balanced chemical equation from the last question to solve this
LenKa [72]
<h3>Answer:</h3>

0.6 g NaCl

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

  • Using Dimensional Analysis
<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Balanced] Na₂CO₃ (aq) + CaCl₂ (aq) → CaCO₃ (s) + 2NaCl (aq)

[Given] 0.5 g Na₂CO₃ reacted with excess CaCl₂

<u>Step 2: Identify Conversions</u>

[RxN] Na₂CO₃ → 2NaCl

Molar Mass of Na - 22.99 g/mol

Molar Mass of C - 12.01 g/mol

Molar Mass of O - 16.00 g/mol

Molar Mass of Cl - 35.45 g/mol

Molar Mass of Na₂CO₃ - 2(22.99) + 12.01 + 3(16.00) = 105.99 g/mol

Molar Mass of NaCl - 22.99 + 35.45 = 58.44 g/mol

<u>Step 3: Stoichiometry</u>

  1. Set up:                    \displaystyle 0.5 \ g \ Na_2CO_3(\frac{1 \ mol \ Na_2CO_3}{105.99 \ g \ Na_2CO_3})(\frac{2 \ mol \ NaCl}{1 \ mol \ Na_2CO_3})(\frac{58.44 \ g \ NaCl}{1 \ mol \ NaCl})
  2. Multiply/Divide:                                                                                               \displaystyle 0.551373 \ g \ NaCl

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 1 sig fig.</em>

0.551373 g NaCl ≈ 0.6 g NaCl

5 0
2 years ago
Question
Nonamiya [84]

Answer:

1.7 mL

Explanation:

start with formula M1V1=M2V2

then plug in values (3)V1=(100)(.05) and solve for V1

V1= 1.66

5 0
2 years ago
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