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3 years ago

Which of Einstein's theories was most important?

Physics

1 answer:

Montano1993 [528]3 years ago

5 0

Answer:

Einstein's theory of general relativity predicted that the space-time around Earth would be not only warped but also twisted by the planet's rotation. Gravity Probe B showed this to be correct.

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Helen is driving her car if the kinetic energy of the car is 8.10 E4 J and the mass of the car and its contents is 1010 kg Helen

larisa86 [58]

( 8.10) x 10^4 J = ½(1010kg)V²
......................= 505V² 
( 8.10) x 10^4 J =[(.0505) x 10^4] V² ........<==10^4 cancels 
8.10 = .0505 V² 
.........______ 
V = ²√ 160.4 

V= 12.6 m/s 

(that's 12.6m/sec(1km/1000m)(3600secs/1hr) = 45.36kph) 
 my diagram is wrong, it is just an ordinary car,

6 0

3 years ago

An explosion that destroys a massive star is called a

BigorU [14]

B) is the correct answer hope this helps

4 0

3 years ago

Read 2 more answers

How do particles move differently in transverse waves and in surface water waves?

elixir [45]

The particles always move parallel and perpendicular to the waves. The waves which are in the water moves a circle. Both up and down and back and forth.

Good luck :)

3 0

3 years ago

Three cars (car F, car G, and car H) are moving with the same speed and slam on their brakes. The most massive car is car F, and

Crazy boy [7]

To solve this problem it is necessary to apply the concepts related to Normal Force, frictional force, kinematic equations of motion and Newton's second law.

From the kinematic equations of motion we know that the relationship of acceleration, velocity and distance is given by

$v_f^2=v_i^2+2ax$

Where,

$v_f =$ Final velocity

$v_i =$ Initial Velocity

a = Acceleration

x = Displacement

Acceleration can be expressed in terms of the drag coefficient by means of

$F_f = \mu_k (mg) \rightarrow$ Frictional Force

$F = ma \rightarrow$ Force by Newton's second Law

Where,

m = mass

a= acceleration

$\mu_k =$ Kinetic frictional coefficient

g = Gravity

Equating both equation we have that

$F_f = F$

$\mu_k mg=ma$

$a = \mu_k g$

Therefore,

$v_f^2=v_i^2+2ax$

$0=v_i^2+2(\mu_k g)x$

Re-arrange to find x,

$x = \frac{v_i^2}{2(-\mu_k g)}$

The distance traveled by the car depends on the coefficient of kinetic friction, acceleration due to gravity and initial velocity, therefore the three cars will stop at the same distance.

3 0

3 years ago

There is a 247–m–high cliff at Half Dome in Yosemite National Park in California. Suppose a boulder breaks loose from the top of

Cerrena [4.2K]

Answer:

Vf = 69.61 m/s

Explanation:

We will use the third equation of motion to solve this problem:

$2gh = V_{f}^2 - V_{i}^2\\$

where,

g = acceleration due to gravity = 9.81 m/s²

h = height of cliff = 247 m

Vf = final velocity = ?

Vi = initial velocity = 0 m/s (boulder breaks loose from rest)

Therefore,

$(2)(9.81\ m/s^2)(247\ m) = V_{f}^2 - (0\ m/s)^2\\V_{f} = \sqrt{4846.14\ m^2/s^2}\\$

Vf = 69.61 m/s

8 0

3 years ago