Answer:
Incomplete question: 9.9 mL of 0.01 M EDTA, and 10 mL of buffer with a pH of 4.
The concentration of [HY³⁻] is 1.8x10⁻²⁸mol/L
Explanation:
Given information:
10 mL of 0.01 M VOSO₄ = 0.01 L
9.9 mL of 0.01 M EDTA = 0.0099 L
10 mL of buffer = 0.01 L
pH of 4
Question: Calculate HY³⁻, [HY³⁻] = ?
Moles of EDTA:
The concentration of Y⁴⁺:
At pH = 4 Y⁴⁻ = 3.8x10⁻⁹
mol/L
The concentration of [H₂Y²⁻]:
The reaction:
H₂Y²⁻ → H⁺ + HY³⁻
The concentration of HY³⁻
Solving for HY³⁻
[HY³⁻] = 1.8x10⁻²⁸mol/L
The over all order of the reaction with the rate law of rate=k[A][B] is 2 since the exponent for [A] is 1 and the exponent for [B] is 1 and 1+1=2.
for example the order for the rate law rate=[A]²[B] is 3 since 2+1=3 and the order for a rate law of rate=[A]²[B]³ the order would be 5 since 2+3=5.
I hope this helps. Let me know if anything is unclear.
Answer
Same amount of protons and neutrons
Explanation
Atoms are electrically neutral because they have equal numbers of protons (positively charged) and electrons (negatively charged). If an atom gains or loses one or more electrons, it becomes an ion.