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elena-14-01-66 [18.8K]
3 years ago
13

How many six digit number can be made from the digits 1, 1, 1, 2, 2, 3?

Mathematics
1 answer:
yulyashka [42]3 years ago
3 0
The permutation of all digits is 6!, but we don't differentiate the same digits, so we divide it by the number of permutations of 1's (3!) and 2's (2!)

\dfrac{6!}{3!2!}=\dfrac{4\cdot5\cdot6}{2}=60

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Answer:

4

Step-by-step explanation:

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Describe the steps you take to order 5/8(5 on top, 8 on bottom fraction), 0.8, 3/5(3 on top)
sergeinik [125]
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3 years ago
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Step-by-step explanation:

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4 0
2 years ago
What is the sum of the geometric series
Sergio039 [100]
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Explanation

I will do this for you in two forms: 1) adding each term, and 2) using the general formula for the sum of geometric series.

1) Adding the terms:

 4
∑ 3 (3/4)^i = 3 (3/4)^0 + 3 (3/4)^1 + 3 (3/4)^2 + 3 (3/4)^3 + 3 (3/4)^4
i=0

= 3 + 9/4 + 27/16 + 81/64 + 243/256 = [256*3 + 27*16 + 64*9 + 4*81 + 243] / 256 =

= 2343 / 256

2) Using the formula:

n-1
∑ A (r^i) = A [1 - r^(n) ] / [ 1 - r]
i=0

Here n - 1 = 4 => n = 5

r = 3/4

A = 3

Therefore the sum is 3 [ 1 - (3/4)^5 ] / [ 1 - (3/4) ] =

= 3 [ 1 - (3^5) / (4^5) ] / [ 1/4 ] = 3 { [ (4^5) - (3^5) ] / (4^5) } / {1/4} =

= (3 * 781) / (4^5) / (1/4) =  3 * 781 / (4^4) = 2343 / 256

So, no doubt, the answer is 2343 / 256
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3 years ago
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stepladder [879]

Answer:

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Step-by-step explanation:

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