The molar mass of the gas : 18 x 10⁻³ kg/mol
<h3>Further explanation</h3>
Given
An unknown gas has one third the root mean square speed of H2 at 300 K
Required
the molar mass of the gas
Solution
Average velocities of gases can be expressed as root-mean-square (V rms)
T = temperature, Mm = molar mass of the gas particles , kg/mol
R = gas constant 8,314 J / mol K
v rms An unknown gas = 1/3 v rms H₂
v rms H₂ :
V rms of unknown gas =
D. The sand has a higher conductivity.
Answer:
2S02 + O2 ---> 2SO3
<u><em>Its</em><em> </em><em>balanced</em><em> </em><em>now</em><em> </em><em>as</em><em> </em><em>Reactants</em><em> </em><em>=</em><em> </em><em>Products</em><em>.</em><em> </em></u>
Answer:
2. 14
Explanation:
To form Br₂ bond, a total of 14 electrons are needed.
Bromine is an element in the 7th group on the periodic table. It has 7 valence electrons.
- In forming the bromine gas, the two atoms of bromine shares 7 electrons each.
- These electrons are from their outermost shell.
- The outermost shell is the valence shell.
- So, two atoms donating 7 electrons gives 14 electrons.
So, the answer would be 20 cm
