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djverab [1.8K]
3 years ago
5

Look at the following pairs of numbers (x, y).

Mathematics
2 answers:
katrin2010 [14]3 years ago
8 0

Step-by-step explanation:

Taking the first coordinate point (3,16.5)

where x= 3 and y= 16.5

\frac{y}{x}  =  \frac{16.5}{3}

\frac{y}{x}  = 5.5

y = 5.5x

optionB

charle [14.2K]3 years ago
5 0

Answer:

B

Step-by-step explanation:

B. y = 5.5 x

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If f(x) = 3x^2 – 2 and g(x) = 2x + 4, find (f- g)(x).
Andreas93 [3]

Answer:

(f - g)(x) = 3x² - 2x - 6

General Formulas and Concepts:

<u>Pre-Alg</u>

  • Order of Operations: BPEMDAS

Step-by-step explanation:

<u>Step 1: Define</u>

f(x) = 3x² - 2

g(x) = 2x + 4

(f - g)(x) is f(x) - g(x)

<u>Step 2: Evaluate</u>

  1. Substitute:                    (f - g)(x) = 3x² - 2 - (2x + 4)
  2. Distribute -1:                 (f - g)(x) = 3x² - 2 - 2x - 4
  3. Combine like terms:    (f - g)(x) = 3x² - 2x - 6
5 0
3 years ago
The points (3,10) and (5,t) fall on a line with a slope of -4 what t value
Elenna [48]

Answer:

t=2

Step-by-step explanation:

The slope is given by  

m = (y2-y1)/(x2-x1)


We have points (3,10) and (5,t) and the slope is -4

Substituting these in

-4 = (t-10)/ (5-3)

Simplifying

-4 = (t-10) / 2

Multiply by 2 on both sides

-4 = (t-10) / 2 *2

-8 = t-10

Add 10 on both sides

-8+10 = t-10+10

2 = t

4 0
3 years ago
Which statement is true about the result of a rigid transformation?
makkiz [27]
The answer is A
A. The pre-image will be congruent to the image.
3 0
3 years ago
Read 2 more answers
Which description is true about ​ pre-image ABC ​ and ​ image A′B′C′ ​ ?
PtichkaEL [24]

Answer:

It's both, C and D -> first you move than you scale

Step-by-step explanation:

6 0
2 years ago
someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your
Lunna [17]

Answer:

Part A) The area of the figure is 24\ units^{2}

Part B) The perimeter of the figure is 20\ units

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

A=\frac{1}{2}bh

<u>Area of triangle ABD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(9-5)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

<u>Area of triangle BCD</u>

Observing the graph

b=BD=(-2+8)=6\ units

h=(5-1)=4\ units

substitute

A=\frac{1}{2}(6)(4)=12\ units^{2}

The area of the figure is

12\ units^{2}+12\ units^{2}=24\ units^{2}

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

P=AB+BC+CD+AD

we have

A(-5,1),B(-8,5),C(-5,9),D(-2,5)

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Find the distance AB

d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units

Find the distance BC

d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units

Find the distance CD

d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units

Find the distance AD

d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units

substitute the values

P=5+5+5+5=20\ units

7 0
3 years ago
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