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3 years ago

Look at the following pairs of numbers (x, y).

Mathematics

2 answers:

katrin2010 [14]3 years ago

8 0

Step-by-step explanation:

Taking the first coordinate point (3,16.5)

where x= 3 and y= 16.5

$\frac{y}{x} = \frac{16.5}{3}$

$\frac{y}{x} = 5.5$

$y = 5.5x$

optionB

charle [14.2K]3 years ago

5 0

Answer:

Step-by-step explanation:

B. y = 5.5 x

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If f(x) = 3x^2 – 2 and g(x) = 2x + 4, find (f- g)(x).

Andreas93 [3]

Answer:

(f - g)(x) = 3x² - 2x - 6

General Formulas and Concepts:

Pre-Alg

Order of Operations: BPEMDAS

Step-by-step explanation:

Step 1: Define

f(x) = 3x² - 2

g(x) = 2x + 4

(f - g)(x) is f(x) - g(x)

Step 2: Evaluate

Substitute: (f - g)(x) = 3x² - 2 - (2x + 4)
Distribute -1: (f - g)(x) = 3x² - 2 - 2x - 4
Combine like terms: (f - g)(x) = 3x² - 2x - 6

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3 years ago

The points (3,10) and (5,t) fall on a line with a slope of -4 what t value

Elenna [48]

Answer:

t=2

Step-by-step explanation:

The slope is given by

m = (y2-y1)/(x2-x1)

We have points (3,10) and (5,t) and the slope is -4

Substituting these in

-4 = (t-10)/ (5-3)

Simplifying

-4 = (t-10) / 2

Multiply by 2 on both sides

-4 = (t-10) / 2 *2

-8 = t-10

Add 10 on both sides

-8+10 = t-10+10

2 = t

4 0

3 years ago

Which statement is true about the result of a rigid transformation?

makkiz [27]

The answer is A
A. The pre-image will be congruent to the image.

3 0

3 years ago

Read 2 more answers

Which description is true about pre-image ABC and image A′B′C′ ?

PtichkaEL [24]

Answer:

It's both, C and D -> first you move than you scale

Step-by-step explanation:

6 0

3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago