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Lilit [14]
2 years ago
6

Liquid carbon disulfide (CS2) reacts with 44.8 L O2 gas to produce the gases carbon dioxide (CO2) and sulfur dioxide (SO2). What

is the mass of carbon dioxide produced?
Chemistry
2 answers:
Ivanshal [37]2 years ago
7 0

What is the mass of carbon dioxide produced?

29.3 g


What is the mass of sulfur dioxide produced?

85.4 g


When making the calculations, did you need to find the number of moles?

Yes

erik [133]2 years ago
5 0
The balanced chemical reaction is:

CS2 + 3O2 = CO2 + 2SO2

First, we assume that the gases here are ideal and that the reaction is done at STP so that 22.4 L of the gas is equal to 1 mol. We use the reaction and the relation of the substances to calculate what is asked. 

44.8 L (1 mol / 22.4 L) (1 mol CO2 / 2 mol SO2) (44.01 g / mol) = 44.01 g CO2
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From the question you will find that:
one capsule of tamiflu is obtained from 2.6 g of star anise.
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7 0
3 years ago
What is the empirical formula for a compound which contains 67.1 zinc and the rest is oxygen
wolverine [178]

Answer:

The empirical formula is ZnO2

Explanation:

What is the empirical formula for a compound which contains 67.1% zinc and the rest is oxygen?

Step 1: Data given

Suppose the compound has a mass of 100.0 grams

A compound contains:

67.1 % Zinc  = 67.1 grams

100 - 67.1 = 32.9 % oxygen  = 32.9 grams

Molar mass of Zinc = 65.38 g/mol

Molar mass of O = 16 g/mol

Step 2: Calculate moles of Zinc

Suppose the compound is 100 grams

Moles Zn = 67. 10 grams / 65.38 g/mol

Moles Zn = 1.026 moles

Step 3: Calculate moles of O

Moles O = 32.90 grams / 16.00 g/mol

Moles O = 2.056 moles

Step 4: Calculate mol ratio

We divide by the smallest amount of moles

Zn: 1.026/1.026 = 1

O: 2.056/1.026 = 2

The empirical formula is ZnO2

To control this we can calculate the % Zinc for 1 mol

65.38 / (65.38+2*16) = 0.67.1 = 67.2 %

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