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Lilit [14]
3 years ago
6

Liquid carbon disulfide (CS2) reacts with 44.8 L O2 gas to produce the gases carbon dioxide (CO2) and sulfur dioxide (SO2). What

is the mass of carbon dioxide produced?
Chemistry
2 answers:
Ivanshal [37]3 years ago
7 0

What is the mass of carbon dioxide produced?

29.3 g


What is the mass of sulfur dioxide produced?

85.4 g


When making the calculations, did you need to find the number of moles?

Yes

erik [133]3 years ago
5 0
The balanced chemical reaction is:

CS2 + 3O2 = CO2 + 2SO2

First, we assume that the gases here are ideal and that the reaction is done at STP so that 22.4 L of the gas is equal to 1 mol. We use the reaction and the relation of the substances to calculate what is asked. 

44.8 L (1 mol / 22.4 L) (1 mol CO2 / 2 mol SO2) (44.01 g / mol) = 44.01 g CO2
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muminat

Answer: Between 1 and 2.

Explanation:

Half life is the amount of time taken by a radioactive material to decay to half of its original value.

a=\frac{a_o}{2^n}        ............(1)

where,

a = amount of reactant left after n-half lives  = 40

a_o = Initial amount of the reactant  = 100

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Putting in the values we get:

40=\frac{100}{2^n}  

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taking log on both sides

nlog(2)=log(2.5)

n=1.32

Thus half-lives that have elapsed is between 1 and 2

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3 years ago
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<span>STP means standard temperature and pressure at 0°C (273K) and 1 atm (atmosphere). The density of the unknown gas is 0.63 gram per liter. The deal gas equation is PV = nRT. The n is the numer of moles and can be represented as mass of the gas, m, divided by the molar mass, c.  so we have,</span>  

PV = nRT
PV = (m/c)RT
Since the density is d = m/V
Pc = (m/V)RT
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substitute the values into the equation,
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