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galina1969 [7]
3 years ago
9

Balance the following equation in acidic conditions. Cr2+ + H2MoO4 --> Cr3+ Mo

Chemistry
1 answer:
Delvig [45]3 years ago
5 0
Cr^2+ + H2MoO4 + H+ → Cr^3+ + Mo + H2O 
Cr goes from +2 to +3 or loses one e- 
Mo is +6 in H2MoO4 so it goes to 0 gaining 6 e- 
so we must multiply Cr by 6 to balance e- 

6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + H2O 
now we balance the spectators 
take O first - 4 on left then, change the right side 

6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + 4H2O 
now we have 8 H's on the right 
we don't want to touch the H2MoO4 
so we make H+ up to 6 for a total of 8 on the left 

6Cr^2+ + H2MoO4 + 6H+ → 6Cr^3+ + Mo + 4H2O 
Then, It's balanced
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Methane (CH4) undergoes combustion. Which products form? please help will give brainliest if correct
allochka39001 [22]

Answer:

B. CO₂ and H₂O.

Explanation:

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In the case of methane, the balanced reaction is:

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With the above information in mind the correct answer is option B. CO₂ and H₂O.

When the combustion is incomplete, carbon monoxide (CO) is produced as well.

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A car moves at a speed of 50 kilometers/hour. Its kinetic energy is 400 joules. If the same car moves at a speed of 100 kilomete
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ke prop to v^2


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8 0
3 years ago
A gas with 4.0 atmospheres of pressure has a temperature of 27°C.
Gala2k [10]

Answer:

7.462

Explanation:

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6 0
2 years ago
How do you work out question 1a?
Sliva [168]

Answer:

-125 kJ

Explanation:

You calculate the energy required to break all the bonds in the reactants. Then you subtract the energy to break all the bonds in the products.

                     H₂C=CH₂   +    H₂ ⟶    H₃C-CH₃

Bonds:       4C-H + 1C=C     1H-H     6C-H + 1C-C

D/kJ·mol⁻¹:  413       612        436       413      347

The formula relating ΔHrxn and bond dissociation energies (D) is

ΔHrxn = Σ(Dreactants) – Σ(Dproducts)

(Note: This is an exception to the rule. All other thermochemical reactions are “products – reactants”. With bond energies, it’s “reactants – products”. The reason comes from the way we define bond energies.)

<em>For the reactant</em>s:

Σ(Dreactants) = 4 × 413 + 1 × 612 + 1 × 436 = 2700 kJ

<em>For the products:</em>

Σ(Dproducts) = 6 × 413 + 1 × 347 = 2825 kJ

<em>For the system</em> :

ΔHrxn = 2700 - 2825 = -125 kJ

4 0
3 years ago
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