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galina1969 [7]
3 years ago
9

Balance the following equation in acidic conditions. Cr2+ + H2MoO4 --> Cr3+ Mo

Chemistry
1 answer:
Delvig [45]3 years ago
5 0
Cr^2+ + H2MoO4 + H+ → Cr^3+ + Mo + H2O 
Cr goes from +2 to +3 or loses one e- 
Mo is +6 in H2MoO4 so it goes to 0 gaining 6 e- 
so we must multiply Cr by 6 to balance e- 

6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + H2O 
now we balance the spectators 
take O first - 4 on left then, change the right side 

6Cr^2+ + H2MoO4 + H+ → 6Cr^3+ + Mo + 4H2O 
now we have 8 H's on the right 
we don't want to touch the H2MoO4 
so we make H+ up to 6 for a total of 8 on the left 

6Cr^2+ + H2MoO4 + 6H+ → 6Cr^3+ + Mo + 4H2O 
Then, It's balanced
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