Answer:
d. The length of the string is equal to one-half of a wavelength
Explanation:
A stretched string of length L, fixed at both ends, is vibrating in its third harmonic. How far from the end of the string can the blade of a screwdriver be placed against the string without disturbing the amplitude of the vibration
a. The length of the sting is equal to one-quarter of a wavelength.b. The length of the string is equal to the wavelength.c. The length of the string is equal to twice the wavelength.d. The length of the string is equal to one-half of a wavelength
e. The length of the string is equal to four times the wavelength
A stretched string of length L fixed at both ends is vibrating in its third harmonic H
How far from the end of the string can the blade of a screwdriver be placed against the string without disturbing the amplitude of the vibration
d. The length of the string is equal to one-half of a wavelength
There are two points during vibration , the node and the antinode
the node is the point where the amplitude is zero.
from the third harmonics, there are two nodes. The first node is half of the wavelength which is the closest to the fixed point.
for third harmonics=3/2lamda
Λ= 7.36E - 34 m
Use the Broglie wavelength equation.
λ= { h/ mv} * SQRT {1- (v^2/ c^2)}
Answer:
layers of cotton lining the interior
Explanation:
The acceleration of a car with the mass of 1,980kg with a net horizontal force of 1,000 N is 0.51m/s².
<h3>HOW TO CALCULATE ACCELERATION?</h3>
The acceleration of a body can be calculated using the following formula:
a = F ÷ m
Where;
- a = acceleration (m/s²)
- F = Force (N)
- m = mass (kg)
According to this question, a car has a mass of 1980kg and horizontal force of 1000N. The acceleration is as follows:
a = 1000/1980
a= 0.51m/s²
Therefore, the acceleration of a car with the mass of 1,980kg with a net horizontal force of 1,000 N is 0.51m/s².
Learn more about acceleration at: brainly.com/question/12134554
