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4 years ago

Assume it takes 5.00 minutes to fill a 50.0-gal gasoline tank. (1 U.S. gal = 231 in.3).

1 answer:

7 0

   (50 gal / 5 min) x (.0037854 m³/gal) x (1 min / 60 sec)

   = (50 · 0.0037854 · 1) / (5 · 60) m³/sec

   = 0.000631 m³/sec

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At the local swimming pool, the diving board is elevated h = 8.5 m above the pool surface and overhangs the pool edge by L = 2 m

Tasya [4]

Answer:

Part a)

$t_w = \sqrt{\frac{2h}{g}}$

Part b)

$t_w = 1.32 s$

Part c)

$d_w = 6.88 m$

Explanation:

Part a)

As we know that the diver will have zero velocity in vertical direction

so here we can say that

$\Delta y = v_y t + \frac{1}{2}a_y t^2$

$h = \frac{1}{2}gt^2$

$t_w = \sqrt{\frac{2h}{g}}$

Part b)

as we know that

$h = 8.5 m$

$g = 9.81 m/s^2$

so we will have

$t_w = \sqrt{\frac{2(8.5)}{9.81}}$

$t_w = 1.32 s$

Part c)

Distance covered by diver from the edge of the pool is given as

$d_w = L + v_w t_w$

$d_w = 2 + (3.7)(1.32)$

$d_w = 6.88 m$

7 0

4 years ago

Any change in the speed or direction of an object is called ?

kykrilka [37]

Answer:

Force and Motion

Explanation:

Please mark as brainliest

5 0

3 years ago

Read 2 more answers

What is the answer??

kati45 [8]

Answer:

lol do you still need help?

Explanation:

8 0

3 years ago

using hooke's law F spring = k Δ x find the force needed to stretch a spring 2 cm if it has elastic constant of 3 N/cm. A. 2/3 N

Assoli18 [71]

Data:
Hooke represented mathematically his theory with the equation:

F = K * x

On what:
F (elastic force) = ?
K (elastic constant) = 3 N/cm
x (deformation or elongation of the elastic medium) = 2cm

Solving:

 $F = K * x$
$F = 3 \frac{N}{\diagup\!\!\!\!\!\!cm} * 2\diagup\!\!\!\!\!\!cm$
$\boxed{\boxed{F = 6N}}$

Answer:
C. 6 N

4 0

3 years ago

If a generator makes 6000 revolutions in two minutes, how many revolutions does it make each second?

MArishka [77]

50 6000 divided by 120 to get the answer

8 0

4 years ago