Why are the fields of science and math so independent?

Why does stirring increase the rate of dissolution?

gavmur [86]

The correct option is D.

When dissolving a substance in a solvent, stirring the solution will increased the rate at which the substance dissolved. This is because, when one stirs a solution, it exposes more surface area of the solute to the solvent, thus, increasing the interaction between the solute and the solvent. The higher the quantity of the solute that is exposed to the solvent, the higher the rate of dissolution of the solute.

5 0

3 years ago

Read 2 more answers

the pressure of 5.0 L of gas increases from 1.50atm to 1240 mmgh. what is the final volume of the gas, assuming no change in mol

NikAS [45]

Answer:

V₂ = 4.7 L

Explanation:

Given data:

Initial volume = 5.0 L

Initial pressure = 1.50 atm

Final pressure = 1240 mmHg (1240/760 = 1.6 atm)

Final volume = ?

Solution:

P₁V₁ = P₂V₂

V₂ = P₁V₁ / P₂

V₂ = 1.50 atm ×5.0 L/1.6 atm

V₂ = 7.5 atm. L /1.6 atm

V₂ = 4.7 L

6 0

3 years ago

Find if the example is correct or not and explain using CER please. Will give 5/5

ELEN [110]

The Lewis structure the student drew is incorrect. The total number of electrons in bonds and lone pairs is equal to the total number of valence electrons available, then a valid Lewis structure is produced.

The correct structure is the following:

The structure that was drawn by the student was incorrect because the total number of electrons around Oxygen were incorrect, there were 6 instead of 8, which was against the octet rule. The correct structure should have 8 electrons around each atom.

5 0

1 year ago

Using the table below, identify the unknown material that has a mass of 15,06 g and a

kati45 [8]

The unknown material : gold

<h3>Further explanation </h3>

Density is a quantity derived from the mass and volume

Density is the ratio of mass per unit volume

Density formula:

$\large {\boxed {\bold {\rho ~ = ~ \frac {m} {V}}}}$

ρ = density

m = mass

v = volume

mass of unknown the material : 15.06 g

volume = 0.78 ml

The density :

$\tt \rho=\dfrac{m}{V}\\\\\rho=\dfrac{15.06}{0.78}=19.31~g/ml$

materials that match the density: gold

8 0

3 years ago

Perform the calculations and determine the absolute and percent relative uncertainty. Express each answer with the correct numbe

Lana71 [14]

Answer:

Explanation:

Given the equation:

$\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}$

The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.

The first step is to determine the algebraic value on the numerator.

Algebraic value = 9.8 - 231

= 7.49

The absolute uncertainty = $\sqrt{(abs. uncertainty_{v_1})^2+(abs. uncertainty_{v_2})^2}$

absolute uncertainty = $\sqrt{(0.3)^3 + (0.01)^2}$

= $\sqrt{0.09 + 0.0001}$

= 0.300167

∴

[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)

The division process now is:

$\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}$

Relative uncertainty = $\dfrac{(\pm 0.300167)}{7.49}\times 100 \ , \ \dfrac{(\pm 0.6) }{8.5} \times 100$

Relative uncertainty = ±4.007565% , ±7.058824%

$\text{Relative uncertainty} = \sqrt{(4.007565)^2+(7.058824)^2}$

$\text{Relative uncertainty} = \sqrt{16.06057723+49.82699626}$

$\text{Relative uncertainty} = \sqrt{65.88757349}$

$\text{Relative uncertainty} = 8.117116$

≅ 8%

The algebraic value = $\dfrac{7.49}{8.5}$

= 0.881176

≅ 0.88

The percentage of the relative uncertainty = $\dfrac{\text{Absolute uncertainty }}{\text{calculated value} }\times 100$

By cross multiplying:

$\text{Absolute uncertainty} (\%) = \dfrac{\text{relative uncertainty} \times \text{calculated value}}{100}$

$\text{Absolute uncertainty} (\%) = \dfrac{8.117116\times 0.881176}{100}$

$\text{Absolute uncertainty} (\%) = 0.0715260$

$\mathbf{\text{Absolute uncertainty} (\%) \simeq 0.07}$

Finally:

$\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}$

8 0

3 years ago