The correct option is D.
When dissolving a substance in a solvent, stirring the solution will increased the rate at which the substance dissolved. This is because, when one stirs a solution, it exposes more surface area of the solute to the solvent, thus, increasing the interaction between the solute and the solvent. The higher the quantity of the solute that is exposed to the solvent, the higher the rate of dissolution of the solute.
Answer:
V₂ = 4.7 L
Explanation:
Given data:
Initial volume = 5.0 L
Initial pressure = 1.50 atm
Final pressure = 1240 mmHg (1240/760 = 1.6 atm)
Final volume = ?
Solution:
P₁V₁ = P₂V₂
V₂ = P₁V₁ / P₂
V₂ = 1.50 atm ×5.0 L/1.6 atm
V₂ = 7.5 atm. L /1.6 atm
V₂ = 4.7 L
The Lewis structure the student drew is incorrect. The total number of electrons in bonds and lone pairs is equal to the total number of valence electrons available, then a valid Lewis structure is produced.
The correct structure is the following:
The structure that was drawn by the student was incorrect because the total number of electrons around Oxygen were incorrect, there were 6 instead of 8, which was against the octet rule. The correct structure should have 8 electrons around each atom.
The unknown material : gold
<h3>Further explanation </h3>
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:

ρ = density
m = mass
v = volume
mass of unknown the material : 15.06 g
volume = 0.78 ml
The density :

materials that match the density: gold
Answer:
Explanation:
Given the equation:
![\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D)
The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.
The first step is to determine the algebraic value on the numerator.
Algebraic value = 9.8 - 231
= 7.49
The absolute uncertainty = 
absolute uncertainty = 
= 
= 0.300167
∴
[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)
The division process now is:
![\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D%3D%20%5Cdfrac%7B7.49%20%28%5Cpm%200.300167%29%7D%7B8.5%20%28%5Cpm0.6%29%7D)
Relative uncertainty = 
Relative uncertainty = ±4.007565% , ±7.058824%




≅ 8%
The algebraic value = 
= 0.881176
≅ 0.88
The percentage of the relative uncertainty =
By cross multiplying:




Finally:
![\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D%3D%200.88%20%5Cpm%20%280.07%29%20%5Cpm%208%5C%25%7D)