Two particles collide, one of which was initially moving and the other initially at rest. Is it possible for both particles to b
1 answer:
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Answer:
Explanation:
According to Newton's law of Gravitation, the force exerted between two bodies of masses
and
and separated by a distance
is equal to the product of their masses and inversely proportional to the square of the distance:
(1)
Where:
is the Gravitational Constant and its value is
is the mass of the Sun
is the mass of the Earth
is the distance between the Sun and the Earth
Substituting the values in (1):
(2)
Finally:
This is the gravitational force acting on the earth due to the sun
Answer:
11.07Hz
Explanation:
Check the attachment for diagram of the standing wave in question.
Formula for calculating the fundamental frequency Fo in strings is V/2L where;
V is the velocity of the wave in string
L is the length of the string which is expressed as a function of its wavelength.
The wavelength of the string given is 1.5λ(one loop is equivalent to 0.5 wavelength)
Therefore L = 1.5λ
If L = 3.0m
1.5λ = 3.0m
λ = 3/1.5
λ = 2m
Also;
V = √T/m where;
T is the tension = 0.98N
m is the mass per unit length = 2.0g = 0.002kg
V = √0.98/0.002
V = √490
V = 22.14m/s
Fo = V/2L (for string)
Fo = 22.14/2(3)
Fo = 22.14/6
Fo = 3.69Hz
Harmonics are multiple integrals of the fundamental frequency. The string in question resonates in 2nd harmonics F2 = 3Fo
Frequency of the wave = 3×3.69
Frequency of the wave = 11.07Hz
