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3 years ago

What happens to ocean water as it moves from Antarctica to the equator

Physics

1 answer:

Charra [1.4K]3 years ago

5 0

As they move water, ocean currents distribute heat and nutrients around the globe.

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Two vectors have magnitudes 3 and 4 . how are the directions of the two vectors related if: a/the sum has magnitude 7.0

Marina CMI [18]

Same directions
Perpendicular
Opposite directions

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2 years ago

A dairy farmer notices that a circular water trough near the barn has become rusty and now has a hole near the base. The hole is

ryzh [129]

Answer: 2.73m/s

Explanation:

Potential energy of the water is turned into kinetic energy

mgd = mv^2/2

Where m = mass of water

g = acceleration due to gravity = 9.81m/s^2

d = depth of the water = 0.38m

v = velocity of leaking water

m × 9.81 × 0.38 = mv^2/

eliminate m on both sides and multiply through by 2

7.4456 = v^2

v = sqrt(7.4456)

v = 2.73m/s

3 0

2 years ago

Which of the following is a unit of mass?

Bogdan [553]

the answer is c: kilogram

explanation: The standard International System of Units (SI) unit of mass is the kilogram (kg). The kilogram is 1000 grams (g), first defined in 1795 as one cubic decimeter of water at the melting point of ice.

7 0

2 years ago

Read 2 more answers

These three bulbs are powered by the battery. What will happen if the middle light burns out? A. The two other bulbs will go out

Anna11 [10]

Answer:

Explanation:

4 0

3 years ago

Susan's 10.0kg baby brother Paul sits on a mat. Susan pulls the mat across the floor using a rope that is angled 30? above the f

elena-s [515]

Answer:

The speed after being pulled is 2.4123m/s

Explanation:

The work realize by the tension and the friction is equal to the change in the kinetic energy, so:

$W_T+W_F=K_f-K_i$ (1)

Where:

$W_T=T*x*cos(0)=32N*3.2m*cos(30)=88.6810J\\W_F=F_r*x*cos(180)=-0.190*mg*x =-0.190*10kg*9.8m/s^{2}*3.2m=59.584J\\ K_i=0\\K_f=\frac{1}{2}*m*v_f^{2}=5v_f^{2}$

Because the work made by any force is equal to the multiplication of the force, the displacement and the cosine of the angle between them.

Additionally, the kinetic energy is equal to $\frac{1}{2}mv^{2}$ , so if the initial velocity $v_i$ is equal to zero, the initial kinetic energy $K_i$ is equal to zero.

Then, replacing the values on the equation and solving for $v_f$ , we get:

$W_T+W_F=K_f-K_i\\88.6810-59.5840=5v_f^{2}\\29.097=5v_f^{2}$

$\frac{29.097}{5}=v_f^{2}\\\sqrt{5.8194}=v_f\\2.4123=v_f$

So, the speed after being pulled 3.2m is 2.4123 m/s

8 0

2 years ago