<u>Answer:</u>
2N/cm
<u>Step-by-step explanation:</u>
According to the Hooke's Law, the force required to extend or compress a spring is directly proportional distance you can stretch it, which is represented as:
where, is the force which is stretching or compressing the spring,
is the spring constant; and
is the distance the spring is stretched.
Substituting the given values to find the elastic constant to get:
Therefore, the elastic constant is 2 Newton/cm.
Answer:
The dog has more momentum than the pony.
Explanation:
To solve this problem, we must remember the formula for calculating momentum, which is given below:
momentum = p = m*v
where m represents the mass of the object and v represents the velocity of the object
Using this knowledge, let's calculate the momentum for the dog and the pony.
Dog: p = m*v = (2kg)*(41 m/s) = 82 kg*m/s
Pony: p = m*v = (75kg)*(1 m/s) = 75 kg*m/s
Since 82 > 75, we can conclude that the dog has more momentum.
Hope this helps!
The answer i believe is A hope it helps
Disclaimer: I just answered this, here is the answer again!
*Used copy paste from my own answer as it is a repeated question, no copied work*
3. A
The relation between V and I at constant R is;V=IR, so it is a direct linear relation.
4. A
This is another direct linear relation as P=IV.
5. D
The relation between P, R, and V is P=, so P is inversely proportional to R.
6.B
The relation between P,I, and R is , so P is directly proportional to the square of I.
Please note that y:x relations are always straight lines while relations are parabolic lines.
Hope this helps!
The question is missing, however, I guess the problem is asking for the value of the force acting between the two balls.
The Coulomb force between the two balls is:
where
is the Coulomb's constant,
is the intensity of the two charges, and
is the distance between them.
Substituting these numbers into the equation, we get
The force is repulsive, because the charges have same sign and so they repel each other.