Answer:
90m
Explanation:
Let g = 9.8 m/s2. The friction is the product of normal force and its coefficient, and normal force is equal to gravity
The acceleration caused by friction, according to Newton's 2nd law:
For the friend to slide over, then the centripetal acceleration must be equal to friction acceleration.
Since you are driving at a constant speed of 21 m/s, then your maximum radius of curvature can be calculated using the following formula:
There is no movement in line C and the greatest velocity occurs at line D. The answers are:
1. 0.5 m/s
2. 0.25 m/s
3. 14m and -2m
4. -1 m/s
<h3>
What is Position - time Graph ?</h3>
Position time graph is the graph of distance or displacement against time. The slope of the graph is velocity.
The given positions of four objects as a function of time are shown
on the graph to the right.
1.) The velocity of object A will be the slope m of the line A.
Slope m = Δx / Δt
m = (4 - 0) / (8 - 0)
m = 4 / 8
m = 0.5 m/s
Velocity at A = 0.5 m/s
2.) The average velocity of object B will be the slope m of the line B.
Slope m = Δx / Δt
m = (6 - 4) / (8 - 0)
m = 2 / 8
m = 0.25 m/s
The average velocity of object B is 0.25s
3.) The object moved a total distance during the first eight seconds will be 4m for A, 2m for B, and 8m for D
Total distance = 4 + 2 + 8 = 14m
It’s net displacement during the same time will be 2. That is,
Displacement = 8 - 6 = -2m
4.) The greatest speed occurred at line D. The velocity of the object moving at the greatest speed will be the slope of the line D
V = -Δx / Δt
V = -8/8
V = -1 m/s
Therefore, there is no movement in line C and the greatest velocity occurs at line D.
Learn more about velocity time graph here :brainly.com/question/769606
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Answer:
v2 = 27.3m/s
Explanation:
Assuming forward as positive.
Mass = m1 = 64kg
Let v be the common velocity of the student and the skateboard.
mass of skateboard = m2 = 5.94kg
v = 1.4m/s
Since the skateboard and the student are initially moving together at the same velocity their momentum together is
(m1 + m2)v
Let the final velocity of the student be v1 and the final velocity of the skateboard be v2
v1 = – 1.0m/s (falls backwards that's why the velocity is negative since we are assuming forward as positive)
Then from conservation of momentum, momentum before is equal to momentum after.
(m1 + m2)v = m1v1 + m2v2
m2v2= (m1 + m2)v – m1v1
v2 = ( (m1 + m2)v – m1v1)/m2
v2 = ( (64 + 5.94)×1.4 – 64×(-1.0))/5.94
v2 = ( (64 + 5.94)×1.4 + 64×1.0)/5.94
v2 = 27.3m/s
Answer:
Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion. Displacement is a vector quantity that refers to "how far out of place an object is"; it is the object's overall change in position.
Explanation:
Answer:
The moment arm is 0.6 m
Explanation:
Given that,
First force 
Second force 
Distance r = 0.2 m
We need to calculate the moment arm
Using formula of torque
So, Here,
We know that,
The torque is the product of the force and distance.
Put the value of torque in the equation
Where, 
=First force
=First force
=Second force
= distance
Put the value into the formula
Hence, The moment arm is 0.6 m
