Using the following formula for linear-motion, the missing variable can be solved:
s = Vi * t + 1/2 (a * t^2)
Where: s = displacement = 29.7 m
Vi = initial velocity = 8.5 m/s
a = acceleration = 9.8
t = time = ?
Substituting:
29.7 = 8.5t + 1/2 (9.8*t^2)
29.7 = 8.5t + 4.9t^2
Dividing both sides by 4.9:
6.06 = 1.73t + t^2
t^2 + 1.73t - 6.06 = 0
(t - 1.74)(t + 3.48) = 0
t = 1.74s
From the above values, the correct answer is 1.74 seconds.
Answer:
16m/s
Explanation:



Therefore, the speed after 8 seconds is 16m/s
Answer:
Explanation:
The work (W) done on the cube to be pushed across the floor is equal to the total thermal energy (ΔE) of the system:
(1)
Also, the work done on the cube by the horizontal force is giving by:
(2)
<em>where F: force applied to the cube , d: displacement of the cube </em>
<em>By equaling the equations (1) and (2)</em>, we can find the thermal energy of the floor:


So, the increase in the thermal energy of the floor is 51 J.
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