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Alexandra [31]
2 years ago
12

Instruction Active

Physics
2 answers:
ElenaW [278]2 years ago
8 0

Explanation:

will your friend be here next weekend

nikklg [1K]2 years ago
4 0

If the distance between two objects decrease and the masses of the objects remain the same, then the force of gravity between the two objects

<u>Answer:</u>

increases

Explanation:

The formula of gravitational force is given as:

F=G Mm/r^2

G = gravitational constant

M, m = Masses of two different objects in which the force is acting.

r = distance between both the objects.

As we can see from the formula that the force of gravity is inversely proportional to the square of the distance between both objects.

When the distance between both objects with the same masses decreases the gravitational force between them increases. Hence the correct answer is option B.

Illamends had the exact same answer from a similar question. Credit goes to her

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What happens In a nuclear fission reaction
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Explanation:

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5 0
3 years ago
Describe the motion of a swing that requires 6 seconds to complete one cycle. What is its period and the frequency? Round to the
shutvik [7]

Period = 6 seconds and frequency = 0.167Hz .

<u>Explanation:</u>

We have , the motion of a swing that requires 6 seconds to complete one cycle. Period is the amount of time needed to complete one oscillation . And in question it's given that 6 seconds is needed to complete one cycle. Hence ,Period of the motion of a swing is 6 seconds . Frequency is the number of vibrations produced per second and is calculated with the formula of  \frac{1}{t} . SI unit of frequency is Hertz or Hz. We know that time period is 6 seconds so frequency =   \frac{1}{t}

⇒ frequency = \frac{1}{time}

⇒ frequency = \frac{1}{6}

⇒ frequency = 0.167Hz

Therefore , Period = 6 seconds and frequency = 0.167Hz .

7 0
3 years ago
If you push a crate across a factory floor at constant speed in a constant direction, what is the magnitude of the force of fric
poizon [28]

Answer:

The magnitude of the force of friction equals the magnitude of my push

Explanation:

Since the crate moves at a constant speed, there is no net acceleration and thus, my push is balanced by the frictional force on the crate. So, the magnitude of the force of friction equals the magnitude of my push.

Let F = push and f = frictional force and f' = net force

F - f = f' since the crate moves at constant speed, acceleration is zero and thus f' = ma = m (0) = 0

So, F - f = 0

Thus, F = f

So, the magnitude of the force of friction equals the magnitude of my push.

3 0
3 years ago
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