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CaHeK987 [17]
3 years ago
6

Temperature for freezing point in°C

Chemistry
2 answers:
bearhunter [10]3 years ago
8 0
It's 0 if it's water
Murrr4er [49]3 years ago
5 0
For which element?...
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Breathe in air container more ____ than breathed out air
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Answer:

c

Explanation:

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Where did the longest tsunami form?
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July 9, 1958: in Lituya Bay<span>, Alaska was caused by a landslide triggered by an 8.3 magnitude earthquake.</span>
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What else is produced when sodium carbonate decomposes? Na2CO3 Na2O +
andriy [413]

When a single compound breaks down into two or more compounds or elements in a chemical reaction then it is known as decomposition reaction.

The chemical symbol for sodium carbonate is Na_2CO_3.

The decomposition of sodium carbonate is:

Na_2CO_3\rightarrow Na_2O+ CO_2

The decomposition of sodium bicarbonate, Na_2CO_3 will result in the formation of sodium oxide, Na_2O and carbon dioxide, CO_2.

Hence, carbon dioxide, CO_2 will produce with sodium oxide, Na_2O on decomposition of Na_2CO_3.

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3 years ago
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Can someone PLEASE HELP me? <br><br> How can you tell if a bond is Covalent?
g100num [7]
There is a couple different ways to determine if a bond is ionic orcovalent. By definition, an ionicbond is between a metal and a nonmetal, and a covalent bond is between 2 nonmetals. So you usually just look at the periodic table and determine whether your compound is made of a metal/nonmetal or is just 2 nonmetals.
6 0
3 years ago
The first-order rate constant for the reaction of methyl chloride (CH3Cl) with water to produce methanol (CH3OH) and hydrochlori
Dvinal [7]

Answer:

K(48.5°C) = 1.017 E-8 s-1

Explanation:

  • CH3Cl + H2O → CH3OH + HCl

at T1 = 25°C (298 K) ⇒ K1 = 3.32 E-10 s-1

at T2 = 48.5°C (321.5 K) ⇒ K2 = ?

Arrhenius eq:

  • K(T) = A e∧(-Ea/RT)
  • Ln K = Ln(A) - [(Ea/R)(1/T)]

∴ A: frecuency factor

∴ R = 8.314 E-3 KJ/K.mol

⇒ Ln K1 = Ln(A) - [Ea/R)*(1/T1)]..........(1)

⇒ Ln K2 = Ln(A) - [(Ea/R)*(1/T2)].............(2)

(1)/(2):

⇒ Ln (K1/K2) = (Ea/R)* (1/T2-1/T1)

⇒ Ln (K1/K2) = (116 KJ/mol/8.3134 E-3 KJ/K.mol)*(1/321.5 K - 1/298 K)

⇒ Ln (K1/K2) = (13952.37 K)*(- 2.453 E-4 K-1)

⇒ Ln (K1/K2) = - 3.422

⇒ K1/K2 = e∧(-3.422)

⇒ (3.32 E-10 s-1)/K2 = 0.0326

⇒ K2 = (3.32 E-10 s-1)/0.0326

⇒ K2 = 1.017 E-8 s-1

7 0
3 years ago
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