Answer:
ΔH°rxn = - 433.1 KJ/mol
Explanation:
- CH4(g) + 4Cl2(g) → CCl4(g) + 4HCl(g)
⇒ ΔH°rxn = 4ΔH°HCl(g) + ΔH°CCl4(g) - 4ΔH°Cl2(g) - ΔH°CH4(g)
∴ ΔH°Cl2(g) = 0 KJ/mol.....pure element in its reference state
∴ ΔH°CCl4(g) = - 138.7 KJ/mol
∴ ΔH°HCl(g) = - 92.3 KJ/mol
∴ ΔH°CH4(g) = - 74.8 KJ/mol
⇒ ΔH°rxn = 4(- 92.3 KJ/mol) + (- 138.7 KJ/mol) - 4(0 KJ/mol) - (- 74.8 KJ/mol)
⇒ ΔH°rxn = - 369.2 KJ/mol - 138.7 KJ/mol - 0 KJ/mol + 74.8 KJ/mol
⇒ ΔH°rxn = - 433.1 KJ/mol
Answer:
Mass = 5.56 g
Explanation:
Given data:
Mass of Cl₂ = 4.45 g
Mass of NaCl produced = ?
Solution:
Chemical equation:
2Cl₂ + 4NaOH → 3NaCl + NaClO₂ + 2H₂O
Number of moles of Cl₂:
Number of moles = mass/molar mass
Number of moles = 4.45 g/ 71 g/mol
Number of moles = 0.063 mol
Now we will compare the moles of Cl₂ with NaCl.
Cl₂ : NaCl
2 : 3
0.063 : 3/2×0.063 =0.095 mol
Mass of NaCl:
Mass = number of moles × molar mass
Mass = 0.095 mol × 58.5 g/mol
Mass = 5.56 g
Answer: the correct option is A ( The spotted coat is an INHERITED TRAIT, and the ability to perform tricks is a LEARNED TRAIT.
Explanation:
Dog is one of the first domesticated animal by man because it has the ability to perceive information and retain it as knowledge for applying to solve problems.
Therefore, the ability to perform tricks is a LEARNED TRAIT. This is so because they have acquired the ability to understand and communicate with humans, and they are uniquely attuned to human behaviors.
INHERITED TRAIT is a trait that can be passed down from one generation to another which are found in genes within the strands of dogs DNA. Some of the inheritable traits includes the following:
- coat color,
- ear type, and.
- tail style.
Therefore the spotted coat is an INHERITED TRAIT
Answer:
[H⁺] = 1.30X10⁻⁴ M
Explanation:
the problem will be solved by using Nernst's equation, which is :
In the given equation
n = 2
Q = ![=\frac{[Zn^{+2}][p_{H2}]}{[H^{+}]^{2}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B%5BZn%5E%7B%2B2%7D%5D%5Bp_%7BH2%7D%5D%7D%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D)
Putting values
![0.53= 0.76 - \frac{0.0592}{n}log(\frac{1X1}{[H^{+}]^{2}})](https://tex.z-dn.net/?f=0.53%3D%200.76%20-%20%5Cfrac%7B0.0592%7D%7Bn%7Dlog%28%5Cfrac%7B1X1%7D%7B%5BH%5E%7B%2B%7D%5D%5E%7B2%7D%7D%29)
on calculating
[H⁺] = 1.30X10⁻⁴ M
Answer:
I think its ethanol based on what I've learned
