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crimeas [40]
2 years ago
13

A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volu

me of the block. Then, use that answer to determine the density of the block. *
Physics
1 answer:
WINSTONCH [101]2 years ago
4 0

Answer:

6g/cm³

Explanation:

Density is the mass per unit volume of any substance. To solve this problem:

   

   Density  = \frac{mass}{volume}  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = \frac{600}{100}    = 6g/cm³

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Planets A and B have the same size, mass, and direction of travel, but planet A is traveling through space at half the speed of
lord [1]

Planet A is heavier than Planet B

Because Planet A is heavier than Planet B, Planet B will be easier to be moved by gravity causing it to move faster than Planet A.

Hope This Helped : )

6 0
3 years ago
Can you please help - the answer I got so far is 7.624 but when I enter it in my homework in Quest, it i stating that this answe
torisob [31]

Answer:

-7.04

Explanation:

9.8 multipled by -0.719 b

6 0
3 years ago
A machine gun fires 50-g bullets at the rate of 4 bullets per second. The bullets leave the gun at a speed of 1000 m/s. What is
TEA [102]

Answer:

Average recoil force experienced by machine will be 200 N

Explanation:

We have give mass of each bullet m = 50 gram = 0.05 kg

There are 4 bullets

So mass of 4 bullets = 4×0.05 = 0.2 kg

Initial speed of the bullet u = 0 m/sec

And final speed of the bullet v = 1000 m/sec

So change in momentum P=m(v-u)=0.2\times (1000-0)=200kgm/sec

Time is given per second so t = 1 sec

We know that force is equal to rate of change of momentum

So force will be equal to F=\frac{200}{1}=200N

So average recoil force experienced by machine will be 200 N

5 0
3 years ago
What does a Lewis structure diagram represent?
densk [106]

Answer:

correct me if i'm wrong nut i thinks its a The atomic symbol of an element surrounded by valence electrons

Explanation:

5 0
3 years ago
Read 2 more answers
Four springs with the following spring constants, 113.0 N/m, 65.0 N/m, 102.0 N/m, and 101.0 N/m are connected in series. What is
Llana [10]

Answer:

K_e_q=22.75878093\frac{N}{m}

f=1.363684118Hz

Explanation:

In order to calculate the equivalent spring constant we need to use the next formula:

\frac{1}{K_e_q} =\frac{1}{K_1} +\frac{1}{K_2} +\frac{1}{K_3} +\frac{1}{K_4}

Replacing the data provided:

\frac{1}{K_e_q} =\frac{1}{113} +\frac{1}{65} +\frac{1}{102} +\frac{1}{101}

K_e_q=22.75878093\frac{N}{m}

Finally, to calculate the frequency of oscillation we use this:

f=\frac{1}{2(pi)} \sqrt{\frac{k}{m} }

Replacing m and k:

f=\frac{1}{2(pi)} \sqrt{\frac{22.75878093}{0.31} } =1.363684118Hz

4 0
3 years ago
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