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crimeas [40]
2 years ago
13

A student has a rectangular block. It is 2 cm wide, 2 cm tall, and 25 cm long. It has a mass of 600 g. First, calculate the volu

me of the block. Then, use that answer to determine the density of the block. *
Physics
1 answer:
WINSTONCH [101]2 years ago
4 0

Answer:

6g/cm³

Explanation:

Density is the mass per unit volume of any substance. To solve this problem:

   

   Density  = \frac{mass}{volume}  

 Since mass = 600g

Let us find the volume;

    Volume  = length x width x height

   Volume  = 25cm x 2cm x 2cm  = 100cm³  

Therefore;

         Density  = \frac{600}{100}    = 6g/cm³

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Answer:

Air resistance have some significant role in projectile motion if the motion lasts for some time.

Explanation:

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  • The trajectory of the projectile with or without air resistance or air drag is totally different.
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An ocean liner leaves New York City and travels 18.0o north of east for 155 km. How far east and how far north has it gone? In o
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Suppose we hang a heavy ball with a mass 13 kg (so the weight is ) from a steel wire 3.9 m long that is 3.1 mm in diameter (radi
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Answer:

1.635×10^-3m

Explanation:

Young modulus is the ratio of the tensile stress of a material to its tensile strain.

Young modulus = Tensile stress/tensile strain

Tensile stress = Force/Area

Given force = 130N

Area = Πr² = Π×(1.55×10^-3)²

Area = 4.87×10^-6m²

Tensile stress = 130/4.87×10^-6 = 8.39×10^7N/m²

Tensile strain = extension/original length

Tensile strain = e/3.9

Substituting in the young modulus formula given young modulus to be 2×10¹¹N/m²

2×10¹¹N/m² = 8.39×10^7/{e/3.9)}

2×10¹¹ = (8.39×10^7×3.9)/e

2×10¹¹e = 3.27×10^8

e = 3.27×10^8/2×10¹¹

e = 1.635×10^-3m

The stretch of the steel wire will be

1.635×10^-3m

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