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Korvikt [17]
3 years ago
7

How many moles of calcium atoms do you have if you have 3.00 × 10²¹ atoms of calcium. (The mass of one mole of calcium is 40.08

g.)
Chemistry
2 answers:
Talja [164]3 years ago
5 0

Answer:

0.0050moles

Explanation:

Since

1 mole=6.022×10^23

X mole=3.0×10^21

Cross multiply

6.022×10^23x=3.0×10^21

Divide both sides by 6.022×10^23

x=0.00498~0.0050moles

So the final answer is 0.0050moles

Nadya [2.5K]3 years ago
3 0

Answer:

4.98x10^-3 mole

Explanation:

According to Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This greatly implies that 1 mole of calcium will also contain 6.02x10^23 atoms.

Now, if 1 mole of calcium contains 6.02x10^23 atoms,

then Xmol of calcium will contain 3x10^21 atoms i.e

Xmol of calcium = 3x10^21/6.02x10^23

Xmol of calcium = 4.98x10^-3mol

Therefore, 4.98x10^-3 mole of calcium contains 3x10^21 atoms

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Answer:

\boxed {\boxed {\sf 2.8 \ m }}

Explanation:

The formula for molality is:

m=\frac{moles \ of \ solute}{kg \ of \ solvent}

There are 0.210 moles of KBr and 0.075 kilograms of pure water.

moles= 0.210 \ mol \\kilograms = 0.075 \ kg

Substitute the values into the formula.

m= \frac{ 0.210 \ mol }{0.075 \ kg}

Divide.

m= 2.8 \ mol/kg= 2.8 \ m

The molality is <u>2.8 moles per kilogram</u>

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