Explanation:
i think it speed hope it helps
Answer:
175s
Explanation:
time it takes sunlight to reach the earth in vacuum
C=light speed=299792458m/s
X=1.5x10^8km=1.5x10^11m
c=X/t
T1=X/c
T1=1.5X10^11/299792458=500.34s
time it takes sunlight to reach the earth in water:
First we calculate the speed of light in water taking into account the refractive index
Cw=299792458m/s/1.349=222233104.5m/s
T2=1.5x10^11/222233104.5m/s=675s
additional time it would take for the light to reach the earth
ΔT=T2-T1=675-500=175s
We have to employ Newton's Second Law and Third Law here: force = mass * acceleration, and every force produces an equal and opposite force.
—The forces vertically are EQUAL, so no acceleration is occurring in this direction. This also means that the force of gravity and the normal force must be equal in magnitude.
—The forces horizontally are NOT equal, so there will be acceleration on this box in this direction. The applied force is going to be larger than the friction force, and the friction force opposes the direction of the applied force.
First, we find the weight of this box, which is given by mass * acceleration due to gravity. On Earth, acceleration due to gravity is about 9.8 m/s^2.
So, 70 kg * 9.8 m/s^2 = 686 N. This force points downwards.
The normal force is equal in magnitude to this, so it is also = 686 N, but points upwards.
The force of friction is given by force(friction) = µ * force(normal). In this problem, µ = 0.50. Then, we plug in to get 0.50 * 686 N = 343 N. This is the force of friction that opposes the motion of the box.
And finally, we are given the applied force, which is 400 N.
Now we make a Newton's second law equation.
force(applied) - force(friction) = mass * acceleration
400 N - 343 N = 70 kg * a
a = .8142 m/s^2
I really hope this is the right answer; it's 4 AM for me lol
<span>Heat transfer is by convection, conduction, or radiation. </span>
In order to fabricate a uniform wire that has a resistance of R = 0.500Ω from 1.00 g of copper and all the copper is to be used, the Length, L of the copper required is 1.82m.
<h3>What would be the length of the copper wire?</h3>
The length of the wire is obtained as follows:
Length, L = √R*m/e*d
where;
R is resistance and is equal to 0.50 Ω
m is mass of the copper and is equal to 1.00 g or 10⁻³ kg
e, resistivity of Copper = 1.7 x 10⁻⁸ Ω⁻¹m
density of copper, d = 8.92 x 10³ kg/m³
L = √(10⁻³ * 0.50/1.7 x 10⁻⁸ * 8.92 x 10³)
Length, L= 1.82m
In conclusion, the length of the wire is obtained from the mass and density of the copper wire.
Learn more about length of wire at: https://brainly.in/question/49182286
#SPJ4