Answer:
t_1 = 0.5*pi*sqrt( m / k )
Explanation:
Given:
- The block of mass m undergoes simple harmonic motion. With the displacement of x from mean position is given by:
x(t) = A*cos(w*t)
Find:
- At what time t1 does the block come back to its original equilibrium position (x=0) for the first time?
Solution:
- The first time the block moves from maximum position to its mean position constitutes of 1/4 th of one complete cycle. So, the required time t_1 is:
t_1 = 0.25*T
- Where, T : Time period of SHM.
- The time period for SHM is given by:
T = 2*pi*sqrt ( m / k )
Hence,
t_1 = 0.25 * 2 * pi * sqrt( m / k )
t_1 = 0.5*pi * sqrt( m / k )
It would be work I assure you
Answer:
A
The distance in revolutions is 
The distance in degrees is 
The distance in radian is 
B

Explanation:
From the question we are told that
The diameter of the pie is 
The distance covered by the rim is 
The number which the pie is divided into is k = 5
Generally the radius of the pie is mathematically represented as

=> 
=> 
Generally the distance covered by the rim is mathematically represented as
=>
=> 
Generally converting to degrees

=> 
=> 
Generally converting to radian

=>
=>
Generally the angular size of one piece of the pie is

=> 
=> 
I believe the correct answer would be zero. The work done in the truck is equal zero since the truck is not moving. Work by definition is the product of force and distance traveled due to the force. In this case, distance is zero giving us a zero work. Hope this helps.