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Nadusha1986 [10]
3 years ago
8

A ball is thrown straight up at time t=0 with an initial speed of 19m/s. Take the point of release to be y0=0 and upwards to be

the positive direction. Calculate the displacement at the time of 0.50 s
Physics
1 answer:
Wittaler [7]3 years ago
4 0
First we write the corresponding kinematics equations:
 a = -g
 v = -g * t + vo
 y = -g * ((t ^ 2) / 2) + vo * t + yo
 Substituting the values:
 y = - (9.81) * (((0.50) ^ 2) / 2) + (19) * (0.50) + (0) = 8.27m
 answer:
 the displacement at the time of 0.50s is 8.27m
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The cheetah is one of the fastest-accelerating animals, because it can go from rest to 16.2 m/s (about 36 mi/h) in 2.4 s. If its
Scilla [17]
<h2>Power of cheetah is 5576.85 W = 7.48 hp</h2>

Explanation:

Power is the ratio of energy to time.

Here we need to consider kinetic energy,

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Initial kinetic energy = 0.5 x Mass x Initial velocity² = 0.5 x 102 x 0² = 0 J

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A series of optical telescopes produced an image that has a resolution of about 0.00350 arc second.
Mila [183]

Answer:

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Explanation:

From the question we are told that

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Therefore

             x =  0.00350  *  \frac{1}{3600 }

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Now  1^o  =  \frac{\pi}{180}

   So  (9.722*10^{-7})^o =  \theta

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The smallest diameter is mathematically represented  as

          D = \frac{1.22 \lambda }{\theta  }

substituting values

           D = \frac{1.22 * 1.7 *10^{-6}} {1.69 *10^{-8}  }

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