Answer:
298,220 N
Explanation:
Let the force on car three is T_23-T_34
Since net force= ma
from newton's second law we have
T_23-T_34 = ma
therefore,
T_23-T_34 = 37000×0.62
T_23= 22940+T_34
now, we need to calculate
T_34
Notice that T_34 is accelerating all 12 cars behind 3rd car by at a rate of 0.62 m/s^2
F= ma
So, F= 12×37000×0.62= 22940×12= 275280 N
T_23 =22940+T_34= 22940+ 275280= 298,220 N
therefore, the tension in the coupling between the second and third cars
= 298,220 N
Answer:
72000 miles
Explanation:
If the distance between the students is 600 miles, and this implies in a 3 degree difference in the sun position, that means this 600 miles is related to 3 degrees of the circunference of the planet.
So, to find the whole circunference of the planet, that is, 360 degrees, we just need to use a rule of three:
3 degrees -> 600 miles
360 degrees -> x miles
3x = 600 * 360
x = 600 * 360 / 3 = 72000 miles
Answer:
The car travel 2.52 m
Explanation:
This problem gives us the time and speed of the car with the echolocation system, and they ask us for the distance traveled, we can use the report motion equation.
Let's start by calculating the relative speed of the two cars, which in this case is the initial mass because the second vehicle is at rest.
v = d / t
d = v t
d = 14 0.18
d = 2.52 m
The car travel 2.52m
This is false. The reaction force can be determined.
Answer:
C
Explanation:
The potential energy decreases because Magnet 1 moves against the magnetic force. If it was increased it would be kinetic