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4 years ago

Which biome contains mostly coniferous trees and receives 35 to 100 cm of rain per year?

Physics

1 answer:

a_sh-v [17]4 years ago

4 0

The question is incomplete as it does not have the options which are:

deciduous forest

taiga (boreal forest)

temperate rainforest

tropical rainforest

Answer:

Taiga (boreal forest)

Explanation:

A Biome refers to the habitat which is occupied by flora and fauna living in similar conditions. These biomes are distinguished based on many features like precipitation, temperature and many other physical factors.

In the given question, the biome which receives an annual rainfall of 35 to 100 cm annually and is mostly covered by the coniferous trees is known as "Taiga biome" which is also known as Boreal forest.

The Taiga biome is one of the largest terrestrial biomes which is present in Eurasia and North America. The biome is characterised by the conifers trees and therefore is also known as the Coniferous trees.

Thus, Taiga (boreal forest) is the correct answer.

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julia-pushkina [17]

M1*V1 + M2*V2 = M1*V + M2*V.
1400*25 + 1800*20[180+40]=1400*V+1800*V.
Divide both sides by 100:
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350 - 276-231i = 32V.
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4 years ago

The planet Jupiter revolves around the Sun in a period of about 12 years (3.79 × 108 seconds). What is its mean distance from th

givi [52]

As we know that gravitational force of Sun will provide the centripetal force to all planets

so here we will have

$F_g = F_c$

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here we know that

$\omega = \frac{2\pi}{T}$

$\omega = \frac{2\pi}{3.79 \times 10^8}$

$\omega = 1.66 \times 10^{-8}$

now from above equation

$\frac{GM}{r^2} = \omega^2 r$

$\frac{GM}{\omega^2} = r^3$

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4 years ago

*Please help this is my final* If the car has a mass of 700 kg, how many newtons of forxe were used to accelerate it 30m/s/s

Vaselesa [24]

Answer:

21,000 N

Explanation:

You would use the formula F=ma

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3 years ago

If f = 136 lb , determine the resultant couple moment.

olga_2 [115]

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4 years ago

A firework is designed so that when it is fired directly upwards, it explodes and splits into three equal-massed parts at its pe

Arturiano [62]

Answer:

the third piece landed $2\,\sqrt{2}$ meters in a direction 45 degrees from the observer's right towards the front

Explanation:

Due to conservation of momentum, the momentum of the third piece must add to the other two momenta in vector from to render zero (initial momentum of the firework on a plane parallel to ground. Therefore the momentum components of the third piece must have a component to the right equal in magnitude to the momentum of the piece that traveled to the left, and a momentum component pointing to the front of the observer of equal magnitude to that of the piece that traveled behind the observer. Then the direction of the third momentum must be at 45 degrees from the observer's right towards the observer's front.

Also, the magnitude of a momentum vector of such components, is given by the Pythagorean theorem. Recall also that the magnitudes of the momentum vectors of the first two pieces must be equal since they traveled equal distances.

$|P_3|=\sqrt{P_1^2+P_2^2} \\|P_3|=\sqrt{P^2+P^2}\\|P_3|=\sqrt{2P^2}\\|P_3|=P\sqrt{2}$

Then the distance traveled by the third piece must also keep this proportionality:

$D_3=\sqrt{2} \,\,D\\D_3=\sqrt{2} \,*\,2\,\,meters\\D_3=2\,\sqrt{2} \,\,meters$

4 0

3 years ago