This year course engages students in becoming skilled readers of prose written in a variety of periods, disciplines, and
rhetorical contexts and in becoming skilled writers who compose for a variety of purposes. More immediately, the course
prepares the students to perform satisfactorily on the A.P. Examination in Language and Composition given in the spring.
Both their writing and their reading should make students aware of the interactions among a writer’s purposes, audience
expectations, and subjects as well as the way generic conventions and the resources of language contribute to effectiveness
in writing. Students will learn and practice the expository, analytical, and argumentative writing that forms the basis of
academic and professional writing; they will learn to read complex texts with understanding and to write prose of
sufficient richness and complexity to communicate effectively with mature readers. Readings will be selected primarily,
but not exclusively, from American writers. Students who enroll in the class will take the AP examination.
Answer: The original volume in liters was 0.0707L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
where,
= initial pressure of gas = 0.85 atm
= final pressure of gas = 456 mm Hg = 0.60 atm (760mmHg=1atm)
= initial volume of gas = ?
= final volume of gas = 94.0 ml
= initial temperature of gas = 
= final temperature of gas = 
Now put all the given values in the above equation, we get:
(1L=1000ml)
Thus the original volume in liters was 0.0707L
Answer:
222.2 grams of CaCl2 in 2 moles
Explanation:
Mole=given mass/gram mass formula
2moles=x/Gram Mass Formula
(Gram Mass Formula of CaCl2):
Ca=40.1
Cl= 35.5 x 2= 71
-----------------------
GFM=111.1
2 moles = x/111.1 g
x=222.2
Answer:
The object placed in the water has a volume of 19 cm³
Explanation:
<u>Step 1: </u>Data given
volume of the cylinder before adding the object = 28 mL = 28 cm³
After adding an object with volume X the volume rises to 47 mL = 47 cm³
<u>Step 2:</u> Calculate the volume of the object
Volume of the object = Final volume - initial volume
Volume of the object = 47 cm³ (or 47 mL) - 28 cm³ ( or 28 mL) = 19 cm³ (or 19 mL)
The object placed in the water has a volume of 19 cm³
Extensive properties, such as mass and volume, depend on the amount of matter being measured. Intensive properties, such as density and color, do not depend on the amount of the substance present. Physical properties can be measured without changing a substance's chemical identity.
