In order to find the molarity of the solution, we first require the moles of acetic acid added. For this,we need the mass which is:
Mass = volume * density
Mass = 50 * 1.05
Mass = 52.5 grams
Moles = mass / molecular weight
Moles = 52.5 / 60.05
Moles = 0.874 mol
Next, we know that the molarity of a solution is:
Molarity = moles / liter
Molarity = 0.874 / 0.5
Molarity = 1.75 M
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Answer:
34,6g of (NH₄)₂SO₄
Explanation:
The boiling-point elevation describes the phenomenon in which the boiling point of a liquid increases with the addition of a compound. The formula is:
ΔT = kb×m
Where ΔT is Tsolution - T solvent; kb is ebullioscopic constant and m is molality of ions in solution.
For the problem:
ΔT = 109,7°C-108,3°C = 1,4°C
kb = 1.07 °C kg/mol
Solving:
m = 1,31 mol/kg
As mass of X = 600g = 0,600kg:
1,31mol/kg×0,600kg = 0,785 moles of ions. As (NH₄)₂SO₄ has three ions:
0,785 moles of ions×
= 0,262 moles of (NH₄)₂SO₄
As molar mass of (NH₄)₂SO₄ is 132,14g/mol:
0,262 moles of (NH₄)₂SO₄×
= <em>34,6g of (NH₄)₂SO₄</em>
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I hope it helps!
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