Answer:
1.005 cm³
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 0.650 cm³
V₂ = ?
P₁ = 1.54 atm
P₂ = 1.01 atm
T₁ = 12°C
T₂ = 16 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (12 + 273.15) K = 285.15 K
T₂ = (16 + 273.15) K = 289.15 K
Using above equation as:
Solving for V₂ , we get:
<u>V₂ = 1.005 cm³</u>
Answer:
Explanation:
Hello there!
In this case, according to the given information, it turns out firstly necessary for us to write the complete molecular equation as shown below:
Now, we can separate the nitrates in ions as they are aqueous to obtain:
And then, we cancel out the nitrate ions as the spectator ones, for us to obtain the net ionic equation:
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Answer:
13.92 %
Explanation:
Mass of = 12.5221 g
Molar mass of = 233.43 g/mol
The formula for the calculation of moles is shown below:
Thus,
Moles of = 0.0536 moles
According to the given reaction,
1 mole of is formed from 1 mole of
Thus,
0.0536 moles of is formed from 0.0536 moles of
Moles of = 0.0536 moles
Moles of sulfur in 1 mole = 1 mole
Moles of sulfur in 0.0536 mole = 0.0536 mole
Molar mass of sulfur = 32.065 g/mol
Mass = Moles * Molar mass = 0.0536 * 32.065 g = 1.7187 g
Mass of ore = 12.3430 g
Mass % = =
= 13.92 %