1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
alexdok [17]
2 years ago
14

Which molecule is produced when two electrons and one proton are added to nadp+?

Chemistry
2 answers:
NeTakaya2 years ago
8 0
The answer is NADPH on apex
Pani-rosa [81]2 years ago
5 0

Answer:

NADPH

Explanation:

Apex

You might be interested in
1. When an element has a positive charge :
natita [175]

Answer:

2) AAAAAA

1)BBBBBBBB

3) I think a or c

8 0
2 years ago
2. Electron A falls from energy level X to energy level Y and releases blue light. Electron B falls from energy level Y to energ
Lynna [10]
Wouldnt you find that on the grid or the table
3 0
2 years ago
Read 2 more answers
Are you my mother? Please answer me...
erastovalidia [21]
No sorry because i'm only 12 years old so no

7 0
3 years ago
Read 2 more answers
Exactly 1.0 mol N2O4 is placed in an empty 1.0-L container and is allowed to reach equilibriumdescribed by the equation N2O4(g)↔
Vilka [71]

Answer : The correct option is, (C) 1.1

Solution :  Given,

Initial moles of N_2O_4 = 1.0 mole

Initial volume of solution = 1.0 L

First we have to calculate the concentration N_2O_4.

\text{Concentration of }N_2O_4=\frac{\text{Moles of }N_2O_4}{\text{Volume of solution}}

\text{Concentration of }N_2O_4=\frac{1.0moles}{1.0L}=1.0M

The given equilibrium reaction is,

                           N_2O_4(g)\rightleftharpoons 2NO_2(g)

Initially                      c                 0

At equilibrium   (c-c\alpha)           2c\alpha

The expression of K_c will be,

K_c=\frac{[NO_2]^2}{[N_2O_4]}

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

where,

\alpha = degree of dissociation = 40 % = 0.4

Now put all the given values in the above expression, we get:

K_c=\frac{(2c\alpha)^2}{(c-c\alpha)}

K_c=\frac{(2\times 1\times 0.4)^2}{(1-1\times 0.4)}

K_c=1.066\aprrox 1.1

Therefore, the value of equilibrium constant for this reaction is, 1.1

4 0
2 years ago
According to the ph scale, what is the approximate ph of ammonia solution?
UNO [17]
I believe that the answer is 11.5
5 0
3 years ago
Other questions:
  • Consider melting ice cream. When it melts, it takes heat away from the environment and so the reaction is endothermic. When you
    15·1 answer
  • Please help, once again. Can't seem to get this...
    9·1 answer
  • At certain times during the process, the temperature increased. During these times, the heat that was absorbed took the form of
    7·1 answer
  • What things are needed to form a hail storm?​
    5·1 answer
  • Which set is an example of an element, a compound, and a mixture?
    6·1 answer
  • What is the difference between acids and strong acids?
    11·1 answer
  • How do you know if you have a balanced equation?
    11·1 answer
  • What is the definition of an Isomer?
    12·2 answers
  • Which of the following is not good conductor of heat?
    8·1 answer
  • Question 4 (1 point)
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!