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fredd [130]
2 years ago
10

How many moles of oxygen do you need to burn one mole of Mg?

Chemistry
1 answer:
kenny6666 [7]2 years ago
4 0

Answer:

You need 0.5 moles of oxygen to burn one mole of Mg.

Explanation:

The balanced reaction is:

2 Mg + O₂ → 2 MgO

When chemical changes occur, the chemical elements are conserved, so the number of atoms is the same before and after the change. To represent this equality of the number of atoms, the expression is "balanced" or "equalized". That's why you put a two in front of the magnesium formula and a two in front of the magnesium oxide to equal the number of atoms involved in the change. These numbers used are called stoichiometric coefficients. The stoichiometric coefficients allow to establish the molar ratio in which the reactants combine and the products are formed.

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction) the following amounts of each compound participate in the reaction:

  • Mg: 2 moles
  • O₂: 1 mole
  • MgO: 2 moles

Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of magnesium reacts with , 1 mole of magnesium reacts with how many moles of oxygen?

amount of moles of oxygen=\frac{ 1 mole of magnesium*1 mole of oxygen}{ 2 moles of magnesium}

amount of moles of oxygen= 0.5 moles

<u><em>You need 0.5 moles of oxygen to burn one mole of Mg.</em></u>

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<h3>Answer:</h3>

1.69 g Mg₃N₂

<h3>General Formulas and Concepts:</h3>

<u>Math</u>

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Chemistry</u>

<u>Atomic Structure</u>

  • Reading a Periodic Table

<u>Stoichiometry</u>

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<h3>Explanation:</h3>

<u>Step 1: Define</u>

[RxN - Unbalanced] Mg + N₂ → Mg₃N₂

[RxN - Balanced] 3Mg + N₂ → Mg₃N₂

[Given] 1.22 g Mg

[Solve] grams Mg₃N₂

<u>Step 2: Identify Conversions</u>

[RxN] 3 mol Mg → Mg₃N₂

[PT] Molar Mass of Mg - 24.31 g/mol

[PT] Molar Mass of N - 14.01 g/mol

Molar Mass of Mg₃N₂ - 3(24.31) + 2(14.01) = 100.95 g/mol

<u>Step 3: Stoich</u>

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  2. [DA] Multiply/Divide [Cancel out units]:                                                         \displaystyle 1.68873 \ g \ Mg_3N_2

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.68873 g Mg₃N₂ ≈ 1.69 g Mg₃N₂

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