Answer:
The concentration of bromic acid (HBrO₃) is 0.069 moles/L
the concentration of hydrofluoric acid (HF) is 0.345 moles/L
Explanation:
(a) The balanced chemical equation for the reaction is
BrF₅ + 3H₂O → HBrO₃ + 5HF
The chemical equation is balanced
(b) To determine the concentration of each acids,
First, we will determine the different volume of the acids yielded
The solution volume is 783 mL = 0.783 L
From the balanced chemical equation,
1 mole of BrF₅ produces 1 mole of HBrO₃
Likewise, 1 mole of BrF₅ will produce 5 moles of HF
From the question,
5.40×10⁻² moles of bromine pentafluoride (BrF₅) reacted;
Hence, 5.40×10⁻² moles of HBrO₃ will be produced
and 5 × 5.40×10⁻² moles of HF will be produced.
Number of moles of HBrO₃ produced = 5.40×10⁻² moles
and Number of moles of HF produced = 2.7 × 10⁻¹ moles
From the formula,
Number of moles (n) = Concentration (C) × Volume (V)
Then,
Concentration (C) = Number of moles (n) / Volume (V)
For bromic acid (HBrO₃)
n = 5.40×10⁻² moles
Volume = 0.783L
Hence,
C = 5.40×10⁻² moles / 0.783L
C = 0.069 moles/L
This is the concentration of bromic acid (HBrO₃)
For hydrofluoric acid (HF)
n = 2.7 × 10⁻¹ moles
V = 0.783L
Hence,
C = 2.7 × 10⁻¹ moles / 0.783L
C = 0.345 moles/L
This is the concentration of hydrofluoric acid (HF)
