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monitta
3 years ago
5

What phases are most common at high temperatures

Chemistry
1 answer:
Nikitich [7]3 years ago
5 0

Answer:

Liquids and gases.

For most substances, when heated to a high enough temperature, the molecules begin moving faster which results in its liquid or gas state.

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If 80% of the moths are dark and you have 80 moths, how<br> many would be dark??
slavikrds [6]

Answer:

the answer is 64 moths are dark

4 0
3 years ago
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If a object has a density of 0.55 g/mL , what is it density in cg/L
Tpy6a [65]

Answer : The density in cg/L is 0.55\times 10^5cg/L.

Solution :

Conversions :    1g/ml=10^{5}cg/L

Conversion of 'g' to 'cg' :    1g=100cg

Conversion of 'L' to 'ml' :    1L=1000ml

Given density = 0.55g/ml

After conversion,

Density = 0.55\times 10^5cg/L

Therefore, the density in cg/L is 0.55\times 10^5cg/L.


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3 years ago
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GalinKa [24]
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8 0
3 years ago
For salt formation procedure crude lidocaine should be dissolved in diethyl ether and 2 ml of 2.2 M sulfuric acid should be adde
mixas84 [53]

Answer:

20 equivalents of sulfuric acid are needed to per equivalent of lidocaine.

Explanation:

To do this calculation we should take in account the key information given:

<em>2 mL (0.02 L) of sulfuric acid (H2SO4) 2.2 M per 1 g of lidocaine (molecular weight=234.34 g/mol)</em>

So we can calculate from here the number of moles of each compound needed for the procedure.

Starting with the sulfuric acid, we know that the molar concentration is defined as [concentration] =n(moles number)/V(volume).

So n=[concentration]*V, and therefore :

n(H2SO4)=2.2 M * 0.02 L=0.044 mol

While the moles of lidocaine can be calculated as n(moles number)=m(mass amount)/mW(molecular weight), so:

n(lidocaine)=m(lidocaine)/mW(lidocaine)= 1 g /234,34 g/mol~0,0043 mol.

Now we can calculate the equivalents.

Take in account that for sulfuric acid, de number of equivalents per mole is 2 (because of the double dissociation of the acid), while the number of equivalents per mole of lidocaine is 1.

Then we can conclude that:

0,0043 equivalents of lidocaine need 0,088 equivalents of sulfuric acid

1 equivalent of lidocaine need (0,088/0.0043)=20,46~20 equivalents of sulfuric acid

Finally, we can conclude that for the described procedure, 20 equivalents of sulfuric acid per equivalent of lidocaine are needed.

4 0
3 years ago
Which of these compounds has 247.83 grams?<br><br>a) H2O<br>b) Fe(OH)3<br>c) CaCl<br>d) Ca(CO2)2
Nonamiya [84]
Your answer would be (D) :)
8 0
3 years ago
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