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hoa [83]
3 years ago
5

A block of mass m witha given inital speed slides down a rough incline with constant speed. If a smaller block that has a mass o

f 4m were placed on the same incline with the same initial speed, it would
a. accelerate down the incline with an acceleration significantly less than that of the smaller block
b. accelerate down the incline with an acceleration significantly greater than that of the smaller block
c. slowly slide down the incline and then stop
d. not move
e. slide down at a constant speed
Physics
1 answer:
arsen [322]3 years ago
7 0

Answer:

c. Slowly slide down the incline and then stop.

Explanation:

The first block slides down a rough incline since friction forces are strong enough to countereffect the effects of gravity forces and friction force is directly proportional to mass. Hence, a greater mass means higher friction forces. Net acceleration is zero.

The smaller block has a greater mass, it slides down the incline and decelerates before stopping. Net acceleration is negative.  

The correct answer is c.

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The car transports 180 m in 12 s. Calculate its speed and express it in m / s and in km / h
makkiz [27]

Explanation:

Given parameters:

Distance  = 180m

Time  = 12s

Unknown:

Speed  in m/s and km/hr

Solution:

Speed is the distance divided by the time taken,

   Speed  = \frac{distance}{time}  

So;

     Speed  = \frac{180}{12}   = 15m/s

   1000m = 1km

  3600s  = 1hr

Therefore;

   15 x m x \frac{1}{s}  x \frac{1km}{1000m} x \frac{3600s}{1hr}    = 54km/hr

5 0
3 years ago
Why vacuum flask is known as thermos flak?
Aneli [31]

The flask was later developed using new materials such as glass and aluminum; however, Dewar refused to patent his invention. ... The name later became a genericized trademark after the term "thermos" became the household name for such a vacuum-insulated container for liquids.

8 0
3 years ago
A spherical shell rolls without sliding along the floor. The ratio of its rotational kinetic energy (about an axis through its c
True [87]

Answer:

The ratio  is  \frac{RE}{TE}  = \frac{2}{3}

Explanation:

Generally  the Moment of inertia of a spherical object (shell) is mathematically represented as

              I  =  \frac{2}{3} *  m r^2

Where m is  the mass of the spherical object

       and   r is the radius  

Now the the rotational kinetic energy can be mathematically represented as

       RE  = \frac{1}{2}*  I *   w^2

Where  w is the angular velocity which is mathematically represented as

             w =   \frac{v}{r}

=>           w^2  =   [\frac{v}{r}] ^2

So

             RE  = \frac{1}{2}*  [\frac{2}{3} *mr^2] *   [\frac{v}{r} ]^2

            RE  = \frac{1}{3} * mv^2

Generally the transnational  kinetic energy of this motion is  mathematically represented as

                TE = \frac{1}{2} mv^2

So  

      \frac{RE}{TE}  =  \frac{\frac{1}{3}  * mv^2}{\frac{1}{2} * m*v^2}

       \frac{RE}{TE}  = \frac{2}{3}

5 0
3 years ago
Deserve to be reborn <br> I need your opinions ?
kvv77 [185]
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6 0
3 years ago
A force of 200 N is applied at piston A, which has a surface area of 4
stira [4]

Answer:

60 cm²

Explanation:

Pressure = Force / Surface area

This is a 2 stage problem which requires working out pressure of piston A and then using that pressure from piston A to calculate the surface area of piston B

Firstly work out pressure of Piston A:

Pressure = 200 / 4

Pressure = 50 N/cm²

Then work out the Surface area of piston B :

Since the pressure is transferred the pressure stays the same so :

Surface area = Force / Pressure

Surface area = 3000 / 50

Surface area = 60 cm²

7 0
4 years ago
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