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Nutka1998 [239]
3 years ago
12

Describe how a new drilling site off the coast of Alaska would be analyzed.

Engineering
1 answer:
Vaselesa [24]3 years ago
8 0

Answer:

People would watch it please give me one star so I can be first place

Explanation:

IDK

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Read the first paragraph of the article.
Paladinen [302]

Answer:

i think it is A, i could not really understand your question.

Explanation:

just a question

(wheres the article?)

5 0
3 years ago
Assume, X Company Limited (XCL) is one of the leading 4th generation Life Insurance
marishachu [46]

Answer:

The issues related to the privacy are:

1. Informational privacy

2. Discrimination factors

3. Biased grouping on the basis of Data mining

4. Lack of consent

5. Morally wrong

6. Illegal distribution of information risks

7. Possibility of threat to life

Let's look at some major concerns:

1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.

2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.

3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.

3 0
3 years ago
Read 2 more answers
Hãy xác định điện áp ngõ ra Về và các dòng điện chạy
Vitek1552 [10]

Answer:

furi has a good reputation for any other business in a few hours of this period of time as per it and the company is not a good place to start and it will have a lot of experience and you have to make a good recovery and you can do something that you can get a lot to be able and you have a lot to

3 0
3 years ago
Consider the diffusion of water vapor through a polypropylene (PP) sheet 1 mm thick. The pressures of H2O at the two faces are 3
Neko [114]

Answer:

\boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}

Explanation:

Diffusion flux of a gas, J is given by

J=P_m\frac {\triangle P}{\triangle x} where P_m is permeability coefficient, \triangle P is pressure difference and x is thickness of membrane.

The pressure difference will be 10,000 Pa- 3000 Pa= 7000 Pa

At 298 K, the permeability coefficient of water vapour through polypropylene sheet is 38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)

Since the thickness of sheet is given as 1mm= 0.1 cm then

J=38\times 10^{-13}(cm^{3}. STP)(cm)/(cm^{2}.s.Pa)\times \frac {7000 pa}{0.1cm}=0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}

Therefore, the diffusion flux is \boxed{0.000000266 \frac {cm^{3}.STP}{cm^{2}.s}}

7 0
3 years ago
Cos square there + cos square theta multiply cot square theta = cot square theta​
Ivahew [28]

Explanation:

We need to prove that : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta=\cot^2\theta

Taking LHS : \cos^2\theta+\cos^2\theta {\cdot} \cot^2\theta

Taking \cos^2\theta common as follows :

\cos^2\theta(1+ \cot^2\theta) ...(1)

We know that :

cosec^2\theta-\cot^2\theta=1\\\\cosec^2\theta=1+\cos^2\theta ....(2)

Use equation (2) in equation (1) as follows :

\cos^2\theta{\cdot} cosec^2\theta

We know that : cosec\theta=\dfrac{1}{\sin\theta}

So,

\cos^2\theta{\cdot} \dfrac{1}{\sin^2\theta}\\\\=\cot^2\theta

=RHS

Hence, LHS = RHS

8 0
3 years ago
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