Solution :
Using the data table for refrigerant-134a at P = 120 psia
∴
For pressure, P = 20 psia
Change in temperature,
Now we find the quality,
The final energy,
Change in internal energy
= 38.09297-40.5485
= -2.4556
Answer:
R min = 28.173 ohm
R max = 1.55 × ohm
Explanation:
given data
capacitor = 0.227 μF
charged to 5.03 V
potential difference across the plates = 0.833 V
handled effectively = 11.5 μs to 6.33 ms
solution
we know that resistance range of the resistor is express as
V(t) = ...........1
so R will be
R = ....................2
put here value
so for t min 11.5 μs
R =
R min = 28.173 ohm
and
for t max 6.33 ms
R max =
R max = 1.55 × ohm