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3 years ago

An astronaut is walking in space. Which of these would have the greatest speed as observed by the astronaut?

2 answers:

4 0

The answer is C) an electromagnetic wave

An electromagnetic wave, which includes electromagnetic radiation such as visible light, moves the fastest of all of the options listed by a significant margin, especially through space. In fact, light travelling through space is technically the theoretical limit of how fast something can travel.

galben [10]3 years ago

4 0

<span>An astronaut is walking in space. Which of these would have the greatest speed as observed by the astronaut. And the answer is C. Electromagnetic Waves

Answer will help you</span>

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A device is rated at 1.3kW when connected to a 120 V source. The equivalent resistance of this device in ohm is:

alexdok [17]

Answer:

correct me if im wrong

brainlest plsss<333

7 0

3 years ago

A particle's position along the x-axis is described by. x(t)= At+Bt^2where t is In seconds: x is in meters: and the constants A

DanielleElmas [232]

Answer

given,

position of particle

x(t)= A t + B t²

A = -3.5 m/s

B = 3.9 m/s²

t = 3 s

a) x(t)= -3.5 t + 3.9 t²

velocity of the particle is equal to the differentiation of position w.r.t. time.

$\dfrac{dx}{dt}=\dfrac{d}{dt}(-3.5t + 3.9t^2)$

$v= -3.5 + 7.8 t$ ------(1)

velocity of the particle at t = 3 s

v = -3.5 + 7.8 x 3

v = 19.9 m/s

b) velocity of the particle at origin

time at which particle is at origin

x(t)= -3.5 t + 3.9 t²

0 = t (-3.5 + 3.9 t )

t = 0, $t=\dfrac{3.5}{3.9}$

t = 0 , 0.897 s

speed of the particle at t = 0.897 s

from equation (1)

v = -3.9 + 7.8 t

v = -3.9 + 7.8 x 0.897

v = 3.1 m/s

6 0

4 years ago

Carbon-14 is used to determine the age of ancient objects. If a sample today contains 0.060 g of carbon-14, how much carbon-14 m

MakcuM [25]

Answer: 86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

Explanation:

Half-life of sample of carbon -14= 5,730 days

$\lambda=\frac{0.693}{t_{\frac{1}{2}}}=\frac{0.693}{5,730 days}=0.00012 day^{-1}$

Let the sample present 11,430 years(t) ago = $N_o$

Sample left till today ,N= 0.060 g

$N=N_o\times e^{-\lambda t}$

$ln[N]=ln[N]_o-\lambda t$

$\log[0.060 g]=\log[N_o]-2.303\times 0.00012 day^{-1}\times 11,430 days$

$\log[N_o]=1.9369$

$N_o=86.47 g$

86.47 g of carbon-14 must have been present in the sample 11,430 years ago.

5 0

3 years ago

Read 2 more answers

Calculate the force of gravity on the 0.50-kg mass if it were 6.4×106 m above earth's surface (that is, if it were two earth rad

Sunny_sXe [5.5K]

Radius of Earth is given as

$R = 6.4 * 10^6 m$

now here the height from the surface of earth is same as that of radius

$h = 6.4 * 10^6 m$

now here the acceleration due to gravity at this height is given as

$g' = \frac{GM}{(R+h)^2}$

$g' = \frac{GM}{4R^2}$

$g' = \frac{g}{4}$

now the force of gravity on the given object will be

$F = mg'$

$F = m*\frac{g}{4}$

$F = 0.5 * \frac{9.8}{4}$

$F = 1.225 N$

<em>so the force of gravity on it is 1.225 N</em>

7 0

3 years ago

a stone is tied to a string and whirled around in a circle at a constant speed. is the string more likely to break when the circ

DochEvi [55]

Answer:

The string is more likely to break when the circle is vertical

Explanation:

The string is more likely to break when the circle is vertical because tension in the string is the same throughout the circular motion and it is equal to mrw^2 when it is rotated in the horizontal plane while tension in the string is maximum and is given by mrw^2+mg when in the vertical plane.

3 0

3 years ago