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Bumek [7]
3 years ago
15

An astronaut is walking in space. Which of these would have the greatest speed as observed by the astronaut?

Physics
2 answers:
Aleks04 [339]3 years ago
4 0
The answer is C) an electromagnetic wave

An electromagnetic wave, which includes electromagnetic radiation such as visible light, moves the fastest of all of the options listed by a significant margin, especially through space. In fact, light travelling through space is technically the theoretical limit of how fast something can travel. 
galben [10]3 years ago
4 0
<span>An astronaut is walking in space. Which of these would have the greatest speed as observed by the astronaut. And the answer is C. Electromagnetic Waves

Answer will help you</span>
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In a 2-dimensional coordinate system, the x- and y-axes are typically _____.
dem82 [27]
<span>In a 2-dimensional coordinate system, the x- and y-axes
are typically perpendicular to each other. (C) </span>
7 0
3 years ago
A 60-kg block initially at rest on a frictionless horizontal surface is acted upon by a force of 3.0 N for a distance of 7.0 m.
Schach [20]

Answer:

Explanation:

Kinetic energy generated = work done by force = force x displacement

= 3 x 7 = 21 J

5 0
3 years ago
What percentage of the takeoff velocity did the plane gain when it reached the midpoint of the runway? a plane accelerates from
ElenaW [278]
When is at the end of the runway the velocity of the plane is given by the equation vf^{2}=0+2*a*s    where s=1800 m is the runway length. Thus
vf^{2}=2*5*1800=18000 (m/s)^{2}      
vf =134.164 (m/s)  

At half runway the velocity of the plane is
v^{2}=2*5* \frac{1800}{2}=9000 ( \frac{m}{s} )^{2}&#10; 
v= \sqrt{9000}=94.87 ( \frac{m}{s})

Therefore at midpoint of runway the percentage of takeoff velocity is
‰P= \frac{v}{vf}=  \frac{94.87}{134.164}=0.707
6 0
3 years ago
A mover applies a net force of 28 N to a sofa that has a mass of 70 kg.
Alinara [238K]

Answer: .4 m/s^2= acceleration

Explanation:

f = m*a

We can rearrange this equation to solve for acceleration. Therefore,

a=f/m

a= 28N/70kg

a= 0.4 m/s^2

8 0
4 years ago
A clock is designed that uses a mass on the end of a spring as a timing mechanism. If the oscillation time needed is exactly one
user100 [1]

Answer:

The value is  k  =  51.34 \  N/ m

Explanation:

From the question we are told that

   The  mass is  m =  1.3 \  kg

   The needed oscillation time is  T = 1 \ s  

 Generally the spring constant is mathematically represented  as

         k  =  \frac{4 \pi^2 * m }{ T^2}

=>      k  =  \frac{4* 3.142^2 * 1.3 }{ 1^2}

=>      k  =  51.34 \  N/ m

5 0
3 years ago
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