Answer:
the science or practice of farming, including cultivation of the soil for the growing of crops and the rearing of animals to provide food, wool, and other products.
Explanation:
Mark me as brainiliest
382.85 Celsius is the temperature does 0.750 moles of an ideal gas occupy a volume of 35.9 L at 114 kPa.
Explanation:
Given data:
number of moles of the gas = 0.75 moles
volume of the gas = 35.9 liters
pressure of the gas = 114 KPa or 1.125 atm
R = 0.0821 latm/moleK
temperature of the gas T = ?
The equation used to calculate temperature from above data is ideal gas law equation.
the equation is :
PV = nRT
T =
Putting the values in the above rewritten equation:
T =
T = 655.9 K
To convert kelvin into celsius, formula used is
K = 273.15+ C
putting the values in the equation
C = 656 - 273.15
= 382.85 Celsius
I would say C 55 000 000 km I’m 80% sure
Cause they can give an estimate how much it weights
Answer:
Heat of combustion = 5.6 ×10³ kj/mol
Explanation:
Given data:
Mass of sucrose = 1.010 g
Initial temperature = 24.92 °C
Final temperature = 28.33 °C
Heat capacity of calorimeter = 4.90 KJ/°C
Heat of combustion = ?
Solution:
ΔT = 28.33 °C - 24.92 °C = 3.41 °C
Q = - c. ΔT
Q = 4.90 KJ/°C . 3.41 °C
Q = - 16.7 kj
Number of moles of sucrose :
Number of moles of sucrose = mass/ molar mass
Number of moles of sucrose = 1.010 g / 342.3 g/mol
Number of moles of sucrose = 0.003 mol
Heat of combustion:
Heat of combustion = Q/n
Heat of combustion = - 16.7 kj/0.003 mol
Heat of combustion = -5.6 ×10³ kj/mol