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3 years ago

5

What is the mass of a block with a volume of 18 cm^3, and a density of 9.2 g/cm^3?

1 answer:

Semmy [17]3 years ago

6 0

Answer: 165.6grams

Explanation:

Mass of a block = ?

Volume of block = 18 cm^3

Density of block = 9.2 g/cm^3

The density of any object depends on its mass and volume.

i.e Density of block = Mass / volume

9.2 g/cm^3 = Mass / 18 cm^3

Mass = 9.2 g/cm^3 x 18 cm^3

= 165.6 g

Thus, the mass of the block is 165.6grams

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Answer:

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Explanation:

From the question we are told that:

Mass of zinc $Mass_{z_n}=2.5g$

Initial conc of HCl $HConc_1=6.0M$

Initial volume of HCl $Hvol_1=20.0mL$

Molar mass of zinc $M_{Z_n}=65.38g/mol$

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$m_{z_n}=\frac{Mass_{Z_n}}{M_{Z_n}}$

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$m_{HCl}=HConc_1*Hvol_1$

$m_{HCl}=6.0M*20.0mL$

$m_{HCl}=6.0M*20.0*10^{-3}L$

$m_{HCl}=0.12\ mol\ HCl$

Generally the reacted moles of HCl $HCl_[reacted]$ is mathematically given by

Since

Zn:HCl =1:2

Therefore

$HCl_[reacted]=0.038*\frac{2}{1}$

$HCl_[reacted]=0.076mol \ HCl$

Generally the moles of HCl after Zn oxidization X is mathematically given by

$x=0.12-0.076$

$x=0.044 mol HCl$

Generally the conc of hydrochloride acid X is mathematically given by

$X=\frac{0.044}{0.020}$

$X=2.2 M Hcl$

Therefore Conc of HCl

$HCl conc=2.2M$

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