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morpeh [17]
3 years ago
15

F2 is light yellow/colorless in hydrocarbon solvent. I2 is pink. If a student combines fluorine water with NaI (sodium iodide) i

n water, then adds pentane and observes a nearly colorless pentane layer, what can the student conclude? F is reduced from F0 to F- F is oxidized I- is oxidized to I0 I is reduced
Chemistry
1 answer:
Tamiku [17]3 years ago
5 0
F₂ + 2 NaI → 2 NaF + I₂
<span>It is given that F₂ is light yellow / colorless in hydrocarbon solvent. The student combines Fluorine water with NaI in water. Then student adds pentane in the mixture of F₂ and NaI. After dissolution, solution was observed and a colorless pentane layer was seen. Alkanes are unreactive in nature. The C-H bond in alkane is difficult to break. whereas, F₂ is very reactive and reacts vigorously with alkanes in presence of light by free radical mechanism.It is given that the color of the solution is nearly colorless. F₂ when present in hydrocarbon solvent is light yellow/ colorless/ nearly colorless. Hence, F₂ is not reacting with hydrocarbon and there is no reaction taking place (No F</span>₂ is present<span>)</span>
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An iron nail rusts when exposed to oxygen. According to the following reaction, how many moles of iron(III) oxide will be formed
Zigmanuir [339]

Answer:

0.453 moles

Explanation:

The balanced equation for the reaction is:

2Fe(s) + 3O2(g)  ==>  2Fe2O3

From the equation,  mass of O2 involved = 16 x 2 x 3 = 96g

                                 mass of Fe2O3 involved = [(2x26) + 3 x 16] x 2

                                                                            = 100g

                Therefore 96g of O2 produced 100g of Fe2O3

                                  32.2g of O2 Will produce   100x32.2/96

                                                   = 33.54g of Fe2O3

Converting it to mole using   number of mole = mass/molar mass

but molar mass of Fe2O3 = 26 + (16 X 3)

                                           = 74g/mole

Therefore number of mole of 33.54g of Fe2O3 = 33.54/74

                                                                           = 0.453 moles

5 0
3 years ago
Predict the formula for a compound made from X3 and Y3–.
PolarNik [594]
Well, a compound has a total charge of 0. So, it's electrically neutral. Since the X is 3+ and the Y is 3- they add to 0. Meaning no subscripts are necessary. Why don't you try a different combo?

Like: 

A^3 and B^1-, to get a 3- charge you need 3xB^1- so the formula is AB3

Does this help?  
3 0
4 years ago
Read 2 more answers
What can you infer about aspirin’s ester group?
Reil [10]

Answer:

Option B, aspirin’s ester group provides greater digestibility to aspirin

Explanation:

Aspirin ester group has three parts

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  2. ester functional group (R-O-CO-R')
  3. aromatic group (benzene ring)

Aspirin is a weak acid and hence it cannot dissolve in water readily. The reaction of Aspirin ester group with water is as follows -

aspirin

(acetylsalicylic acid) + water → salicylic acid + acetic acid

(ethanoic acid)

Aspirin passes through the stomach and remains unchanged until it reaches the intestine where it hydrolyses ester to form the active compound.

8 0
3 years ago
A 1.0l buffer solution contains 0.100 mol of hc2h3o2 and 0.100 mol of nac2h3o2. the value of ka for hc2h3o2 is 1.8×10−5. part a
Mandarinka [93]
There are two ways to solve this problem. We can use the ICE method which is tedious and lengthy or use the Henderson–Hasselbalch equation. This equation relates pH and the concentration of the ions in the solution. It is expressed as

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[HA] is the concentration of the acid

Given:
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HC2H3O2 = 0.1 mol
NaC2H3O2 = 0.1 mol

Solution:
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[HA] = .1 - 0.015 = 0.085 moles

pH = 4.74 + log (.115/0.085)
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B ) its a physical change
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