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3 years ago

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3 Water within a piston–cylinder assembly, initially at 10 lbf/in.2 , 500°F, undergoes an internally reversible process to 80 lb

f/in.2 , 800°F, during which the temperature varies linearly with specific entropy. For the water, determine the work and heat transfer, each in Btu/lb. Neglect kinetic and potential energy effects.

1 answer:

Goryan [66]3 years ago

6 0

Answer:

109.779BTU/lbm and 220.179BTU/lbm

Explanation:

We have the values of Pressure and Temperature,

$P_1 = 10psi\\T_1 = 500\°F\\P_2 = 80psi\\T_2 = 800\°F$

At the tables, this conditions are for enthalpy and specific energy,

$s_1=1.9693BTU/lbm.R\\s_2=1.8704BTU/lbm.R\\u_1=1182.2BTU/lbm\\u_2=1292.6BTU/lbm$

We calculate now the heat transfer for the system,

$q_{1-2}=\frac{T_1+T_2}{2}(s_1-s_2)$

$q_{1-2}=\frac{(500+460)(800+460)}{2}(1.9693-1.8704)$

$q_{1-2}=109.779BTU/lbm$

We can calculate now the work transfer given by,

$w=q-\Delta u$

$w= 109.779-(1182.2-1292.6)$

$w=220.179BTU/lbm$

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3 years ago

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