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Studentka2010 [4]
2 years ago
10

Someone stuck a piece of chewing gum on the outer edge of a blade on a ceiling fan. The radius (r) of where the gum is from the

center of the spinning fan is 0.60m. The period (T) that it takes for the blade to complete one revolution is 0.25seconds on its slowest speed setting. If we estimate the piece of chewed gum to have a mass (m) of 0.0026Kg, then how much centripetal Force (Fc) is on the gum when the fan is spinning at this speed?
Physics
1 answer:
maksim [4K]2 years ago
3 0

Answer: why would u stick a gum there

Explanation:

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Answer:

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Explanation:

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Generally the force acting between the forces is mathematically represented as

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=>     T cos \theta =  \frac{k*  q^2}{ r^2}

Generally from Pythagoras theorem the radius of the circular curve created by the force is

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=>      r = 0.043 \ m  

=>     q = tan \theta * \frac{m * g * r^2 }{k}

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