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Contact [7]
3 years ago
11

Assume you are riding in a plane that is moving at a speed of 600kmh relative to the ground. If you walk from the back to the fr

ont of the airplane at a speed of 1.0 km/h, then your speed relative to the ground is
A. 1.0 km/h
B. 599 km/h
C. 600 km/h
D. 601 km/h​
Physics
1 answer:
jok3333 [9.3K]3 years ago
5 0
C. 600 km/h is the answer for this question
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Colonel John P. Stapp, USAF, participated in studying whether a jet pilot could survive emergency ejection. On March 19, 1954, h
PolarNik [594]

Answer:

(a) a = - 201.8 m/s²

(b) s = 197.77 m

Explanation:

(a)

The acceleration can be found by using 1st equation of motion:

Vf = Vi + at

a = (Vf - Vi)/t

where,

a = acceleration = ?

Vf = Final Velocity = 0 m/s (Since it is finally brought to rest)

Vi = Initial Velocity = (632 mi/h)(1609.34 m/ 1 mi)(1 h/ 3600 s) = 282.53 m/s

t = time = 1.4 s

Therefore,

a = (0 m/s - 282.53 m/s)/1.4 s

<u>a = - 201.8 m/s²</u>

<u></u>

(b)

For the distance traveled, we can use 2nd equation of motion:

s = Vi t + (0.5)at²

where,

s = distance traveled = ?

Therefore,

s = (282.53 m/s)(1.4 s) + (0.5)(- 201.8 m/s²)(1.4 s)²

s = 395.54 m - 197.77 m

<u>s = 197.77 m</u>

6 0
3 years ago
A man is traveling on a bicycle at 14 m/s along a straight road that runs parallel to some railroad tracks. He hears the whistle
deff fn [24]

Answer:

Explanation:

b ) The problem is based on Doppler's effect of sound

f = f₀ x (V - v₀) /( V+v_s)

f is apparent frequency ,f₀ is real frequency , V is velocity of sound , v₀ is velocity of observer going away  , v_s is velocity of source going away

778  = 840 x (340 - 14)/ (340 + v_s)

340 + v_s = 341.18

v_s = 1.18 m /s

it will go  away from   the observer or the cyclist.

speed of train = 1.18 m /s

a )

For a stationary observer v₀ = 0

f = f₀ x V  /( V+v_s)

= 840 x 340 / (340 + 1.180)

= 837 Hz

6 0
3 years ago
What words does convection come from
ludmilkaskok [199]

Answer:

from Late Latin convectionem

Explanation:

6 0
3 years ago
A bowl contains 4 red balls and 2 green balls. Two balls are selected simultanesouly and at random. What is the conditional prob
AlladinOne [14]

Answer:0.6

Explanation:

Given

Bowl contains 4 red and 2 Green balls

Probability of selecting two red balls given atleast one of the ball is red + Probability of selecting two red balls given that no ball is red =1

Probability of selecting two red balls given that no ball is red =\frac{Probability \ of\ selecting\ two\ red\ balls\ out\ of\ 4\ balls}{probability\ of\ selecting\ 2\ balls\ out\ of\ 6 balls}

P=\frac{^{4}C_2}{^{6}C_2}

P=\frac{2}{5}

Required Probability=1-\frac{2}{5}=\frac{3}{5}

7 0
4 years ago
Which of the following wavelengths will produce standing waves on a string that is 3.5 m long?
denpristay [2]

In a string of length L, the wavelength of the n-th harmonic of the standing wave produced in the string is given by:

\lambda=\frac{2}{n} L


The length of the string in this problem is L=3.5 m, therefore the wavelength of the 1st harmonic of the standing wave is:

\lambda=\frac{2}{1} \cdot 3.5 m=7.0 m


The wavelength of the 2nd harmonic is:

\lambda=\frac{2}{2} \cdot 3.5 m=3.5 m


The wavelength of the 4th harmonic is:

\lambda=\frac{2}{4} \cdot 3.5 m=1.75 m


It is not possible to find any integer n such that \lambda=5 m, therefore the correct options are A, B and D.

3 0
3 years ago
Read 2 more answers
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