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egoroff_w [7]
3 years ago
5

A truck is moving around a circular curve at a uniform velocity of 13 m/s. If the centripetal force on the truck is 3,300 N and

the mass of the truck is 1,600 kg, what's the radius of the curve?
A. 6.30 m
B. 81.94 m
C. 109.09 m
D. 348.56 m
Physics
2 answers:
Paladinen [302]3 years ago
4 0
Answer: Option B.

Since here the truck is moving on a circular track, it will experience centripetal force.

F(centripetal) = m × acc 
or 
r = \frac{m v^{2}}{F}

where r is the radius of the track. 
m is the mass of truck
v is the speed  of the truck. 
Given: v = <span>13 m/s
m = </span><span>1,600 kg
</span>F = 3300 Newton

To find = radius of track=?
r = \frac{m v^{2} }{F}
r = \frac{1600*13*13}{3300}
r = 81.94 m
Therefore, radius of track is 81.94 m
I am Lyosha [343]3 years ago
3 0

The Correct answer to this question for Penn Foster Students is: 81.94m

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Answer:

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Explanation:

Electric potential: This can be defined as the work done in bringing a unit charge from infinity to that point against the action of the field. The S.I unit of potential is volt (V)

The formula for potential is

V = kq/r............................ Equation 1

Where V = electric potential, k = proportionality constant, q = charge, r = distance.

making q the subject of the equation,

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Given: V = 490 V, r = 10 m,

Constant: k = 9×10⁹ Nm²/C²

Substitute into equation 2

q = 490(10)/(9×10⁹)

q = 5.4×10⁻⁷ C

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