<h2>0.054×2.33×90</h2><h3>=0.11582×90</h3><h3>=11.3238</h3>
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Answer:
The nervous system handles the stress response, which, if overworked, can eventually lead to diseases ranging from high blood pressure to diabetes.
Explanation:
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Answer:
884 balloons
Explanation:
Assume ideal gas, since temperature is constant, then the product of pressure and volume is constant.
So if pressures reduces from 100 to 1.2, the new volume would be

The spherical volume of each of the balloon of 30cm diameter (15 cm or 0.15 m in radius) is

The number of balloons that 12.5 m3 can fill in is

Answer:
v = 15 [m/s]
Explanation:
To solve this problem we must use the principle of conservation of linear momentum, which tells us that momentum is equal to the product of mass by Velocity.

where:
P = linear momentum [kg*m/s]
m = mass = 2 [kg]
v = velocity = 15 [m/s]
![P=2*15\\P=30 [kg*m/s]](https://tex.z-dn.net/?f=P%3D2%2A15%5C%5CP%3D30%20%5Bkg%2Am%2Fs%5D)
Since we know that momentum is conserved, that is, all momentum is transferred to the second body, we can determine the velocity of the second body, since the mass is equal to that of the first body.
![30=2*v\\v = 30/2\\v = 15 [m/s]](https://tex.z-dn.net/?f=30%3D2%2Av%5C%5Cv%20%3D%2030%2F2%5C%5Cv%20%3D%2015%20%5Bm%2Fs%5D)
Answer:
a) 9.99 s
b) 538 m
c) 20.5 s
d) 1160 m
Explanation:
Given:
x₀ = 0 m
y₀ = 49.0 m
v₀ = 113 m/s
θ = 60.0°
aₓ = 0 m/s²
aᵧ = -9.8 m/s²
a) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find t.
vᵧ = aᵧ t + v₀ᵧ
(0 m/s) = (-9.8 m/s²) t + (113 sin 60.0° m/s)
t ≈ 9.99 s
b) At the maximum height, the vertical velocity vᵧ = 0 m/s. Find y.
vᵧ² = v₀ᵧ² + 2aᵧ (y − y₀)
(0 m/s)² = (113 sin 60° m/s)² + 2 (-9.8 m/s²) (y − 49.0 m)
y ≈ 538 m
c) When the projectile lands, y = 0 m. Find t.
y = y₀ + v₀ᵧ t + ½ aᵧ t²
(0 m) = (49.0 m) + (113 sin 60° m/s) t + ½ (-9.8 m/s²) t²
You'll need to solve using quadratic formula:
t ≈ -0.489, 20.5
Since negative time doesn't apply here, t ≈ 20.5 s.
d) When the projectile lands, y = 0 m. Find x. (Use answer from part c).
x = x₀ + v₀ₓ t + ½ aₓ t²
x = (0 m) + (113 cos 60° m/s) (20.5 s) + ½ (0 m/s²) (20.5 s)²
x ≈ 1160 m