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valina [46]
4 years ago
8

How did settlers changed the great plains?

Physics
1 answer:
Paul [167]4 years ago
6 0
They farmed it and got rid of most of the buffalo. They also caused the locust plague from turning up the eggs in the dirt when it was first plowed.
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A mass of 2.50 kg is in a gravitational field of 14.0 N/kg. What force acts on the mass?
Olenka [21]
To determine the force that acts on the mass, just multiply the mass by the gravitational field. Using the given data,
                             F = (2.50 kg)(14 N/kg) = 35 N
Therefore, the force that acts on the mass is equal to 35 N. 
7 0
3 years ago
Read 2 more answers
PLEASE GUYS I REALLY NEED HELP ASAP. THIS IS SO IMPORTANT, I AM EVEN WILLING TO PAY FOR REAL.
malfutka [58]
 <span>The bending of light rays by sun is twice in Einstein's theory as in Newton's theory of gravitation. Einstein's theory was verified by Eddington during the solar eclipse in 1919 

Also observed precession of aphelion of mercury completely explained by Einstein's theory but not by Newtonian gravity</span>
3 0
3 years ago
Mrs. Stark weighs 70kg. How much Potential Energy does she have if she stands on the roof of an 80m tall building?
sesenic [268]

70kg

1 earth gravity

80 M of height

---------------------------------

54917.2 Joules of energy

Mrs. Stark has 54,917.2 Joules of energy.

3 0
3 years ago
A reciprocating compressor is a device that compresses air by a back-and-forth straight-line motion, like a piston in a cylinder
Stella [2.4K]

Answer:

The temperature change per compression stroke is 32.48°.

Explanation:

Given that,

Angular frequency = 150 rpm

Stroke = 2.00 mol

Initial temperature = 390 K

Supplied power = -7.9 kW

Rate of heat = -1.1 kW

We need to calculate the time for compressor

Using formula of compression

\terxt{time for compression}=\text{time for half revolution}

\terxt{time for compression}=\dfrac{1}{2}\times T

\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{f}

Put the value into the formula

\terxt{time for compression}=\dfrac{1}{2}\times \dfrac{1}{150}\times60

\terxt{time for compression}=0.2\ sec

We need to calculate the rate of internal energy

Using first law of thermodynamics

U=Q-W

\dfrac{\Delta U}{\Delta t}=\dfrac{\Delta Q}{\Delta t}-\dfrac{\Delta W}{\Delta t}

Put the value into the formula

\dfrac{\Delta U}{\Delta t}=(-1.1)-(7.9)

\dfrac{\Delta U}{\Delta t}=6.8\ kW

We need to calculate the temperature change per compression stroke

Using formula of rate of internal energy

\dfrac{\Delta U}{\Delta t}=\dfrac{nc_{v}\Delta \theta}{\Delta t}

\Delta\theta=\dfrac{\Delta U}{\Delta t}\times\dfrac{\Delta t}{n\times c_{c}}

Put the value into the formula

\Delta \theta=6.8\times10^{3}\dfrac{0.2}{2.0\times20.93}

\Delta\theta=32.48^{\circ}

Hence, The temperature change per compression stroke is 32.48°.

6 0
4 years ago
The water that powers the generators enters and leaves the system at a low speed (thus we can neglect its change of kinetic ener
madam [21]

Answer:

Explanation:

Let density of water be ρ .

During flow , volume of water flowing per second is constant

loss of P. E per unit volume  = ρ gh , 83.5 % is lost

Gain of K E per unit volume = 1/2  ρ v²

83.5 % of mgh =   ρ 1/2  ρ v²

1/2  ρ v² =  .835 x 9.8

v² =  2 x .835 x 9.8

= 16.366

v = 4.04 m /s

4 0
4 years ago
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