Answer:
The centripetal acceleration will be "21.785 m/s²".
Explanation:
The given values are:
Time,
t = 0.85 seconds
Length of rope,
r = 0.40 m
Mass of ball,
m = 0.80 kg
As we know,
⇒ 
On substituting the values, we get
⇒ 
⇒ 
⇒ 
The centripetal acceleration will be:
⇒ 
⇒ 
⇒ 
⇒ 
Answer:
Explanation:
<h3>for average velocity we use this formula V Vavg =V1+V2<u>
<em>÷</em></u>
<u>2</u></h3>
To solve this problem we must rely on the equations of the simple harmonic movement that define the period as a function of length and gravity as

Where
l = Length
g = Gravity
Re-arrange to find L,

Our values are given as


Replacing,



Therefore the height would be 25.348m
Answer: D. A wave with a shorter wavelength is always faster than one with a longer wavelength
Explanation: "Imagine two sets of waves that have the same speed. <u><em>If one set has a longer wavelength, it will have a lower frequency (more time between waves). If the other set has a shorter wavelength, it will have a higher frequency</em></u> (less time between waves). Light moves even faster AND has shorter wavelengths."
Why it's not C: "The number of complete wavelengths in a given unit of time is called frequency (f). <em><u>As a wavelength increases in size, its frequency and energy (E) decrease</u></em>. From these equations you may realize that as the frequency increases, the wavelength gets shorter. As the frequency decreases, the wavelength gets longer."
Why it's not B: "The frequency does not change as the sound wave moves from one medium to another. Since the speed changes and the frequency does not, the wavelength must change."
Why it's not A: "Do loud sounds travel faster than soft sounds? No. Both travel at the same speed The speed depends on the medium it passes through. Louder sounds are simply sound waves with higher amplitude traveling at the same speed."
The magnitude of the electric field at the third vertex of the triangle is determined as zero.
<h3>Electric field at the third vertex of the triangle </h3>
The electric field at the third vertex of the equilateral triangle due to the other charges placed on the first and second vertices is calculated as follows;
E = E(13) + E(23)
E = (kq₁)/r² + (kq₂)/r²
where;
- q1 is positive charge
- q2 is negative charge
E = (kq₁)/r² - (kq₂)/r²
E = 0
Thus, the magnitude of the electric field at the third vertex of the triangle is determined as zero.
Learn more about electric field here: brainly.com/question/14372859
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