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xxTIMURxx [149]
3 years ago
7

Drag and drop the words into the correct locations to label the layers of the atmosphere, with the lowest layer at the bottom. (

2 points)
Space

top layer: ___

fourth layer: ___

middle layer: ___

second layer: ___

lowest layer: ___

Earths surface


Word bank:

exosphere

thermosphere

mesophere

tropospere

stratosphere
Physics
2 answers:
professor190 [17]3 years ago
4 0

Answer:

The top layer is exosphere. The fourth is the Thermosphere. The middle layer is the mesophere. The second layer is the Stratospere. the lowest layer is the troposphere

Explanation:

Valentin [98]3 years ago
3 0

Answer:

All the answers are.

Explanation: 1 clouds and possible precipitation

2 each grid point on a three-dimensional get

3 it produces uneven heating of earths surface by the sun

4 C a warm surface current flows along the east coast of the United States and a cold water surface current flows along the West Coast of the United States

5 plate tectonics

6 wet soil absorbs heat more slowly, due to waters high heat capacity

7 top layer: exosphere, fourth layer:thermosphere, middle layer:mesosphere, second layer: stratosphere, lowest layer: troposphere

8 physics that describes how air moves and heat and moisture are exchanged.

I just took the test and these are the correct answers, I hope this helped you.

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How we will measure centimeters
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Answer:

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Explanation:

——»To measure centimeters, we can use ruler.

  • Use a ruler with the side marked either cm or mm. Align the edge of the object with the first centimeter line on the ruler, then find the length in whole centimeters, or the larger numbers on the ruler.
7 0
2 years ago
When a cyclist moves downhill without pedalling, what type of energy does he gain?
Vesna [10]

Answer:

He is gaining kinetic energy and losing potential energy

Explanation:

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2 years ago
Read 2 more answers
A light ray traveling through a material with an index of refraction of 1.2 is incident on a material that has an index of refra
zzz [600]

Answer:

compared to the incident angle, the refracted angle is 45.56⁰

Explanation:

From Snell's law;

n₁sin(I) = n₂sin(r)

Where;

n₁ is the refractive index of light in medium 1 = 1.2

n₂ is the refractive index of light in medium 2 = 1.4

I is the incident angle

r is the refractive angle

n = \frac{1}{sin(I)}\\\\sin(I) = \frac{1}{n}\\\\sin(I) =\frac{1}{1.2}\\\\sin(I) =0.8333\\\\I = sin^-{(0.8333)

I = 56.439⁰

Applying snell's law

n_1sin(I) = n_2sin(r)\\\\sin(r) = \frac{n_1sin(I) }{n_2}\\\\sin(r) = \frac{1.2*sin(56.439) }{1.4}\\\\sin(r) = 0.714\\\\r = sin^-(0.714)\\\\r = 45.56^o

Therefore, compared to the incident angle, the refracted angle is 45.56⁰

3 0
3 years ago
El tubo de entrada que suministra presión de aire para operar un gato hidráulico tiene 2 cm de diámetro. El pistón de salida es
Bess [88]

Answer:

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

Explanation:

Asumiendo que la presión (P), medida en pascales, tiene una distribución uniforme sobre la superficie del pistón, se calcula a partir de la siguiente expresion:

P = \frac{F}{A}

Donde:

F - Fuerza motriz, medida en newtons.

A - Área del pistón, medida en metros cuadrados.

La fuerza motriz es equivalente al peso del automóvil. El área del pistón (A), medido en metros cuadrados, es determinado por:

A=\frac{\pi}{4}\cdot D^{2}

Donde D es el diámetro del pistón, medido en metros.

Si D = 0.32\,m y F =17,640\,N, entonces la presión neumática es:

A = \frac{\pi}{4}\cdot (0.32\,m)^{2}

A \approx 0.080\,m^{2}

P = \frac{17,640\,N}{0.080\,m^{2}}

P = 220,500\,Pa

La presión neumática para levantar un automóvil de 17,640 newtons es 220,500 pascales.

8 0
3 years ago
Two force vectors are oriented such that the angle between their directions is 38 degrees and they have the same magnitude. If t
Usimov [2.4K]

Answer:

Sum of the forces will be equal to 3.479 N

Explanation:

We have given two same forces are oriented at an angle of 38°

Magnitude of each force is given F_1=F_2=1.84

We have to find the sum of the forces

Sum of the forces will be equal to

F=\sqrt{F_1^2+F_2^2+2F_1F_2cos\Theta }

So sum of the forces will be equal to F=\sqrt{1.84^2+1.84^2+2\times 1.84\times 1.84\times cos38^{\circ} }=3.479

So sum of the force will be equal to 3.479 N

6 0
3 years ago
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