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xxTIMURxx [149]
3 years ago
7

Drag and drop the words into the correct locations to label the layers of the atmosphere, with the lowest layer at the bottom. (

2 points)
Space

top layer: ___

fourth layer: ___

middle layer: ___

second layer: ___

lowest layer: ___

Earths surface


Word bank:

exosphere

thermosphere

mesophere

tropospere

stratosphere
Physics
2 answers:
professor190 [17]3 years ago
4 0

Answer:

The top layer is exosphere. The fourth is the Thermosphere. The middle layer is the mesophere. The second layer is the Stratospere. the lowest layer is the troposphere

Explanation:

Valentin [98]3 years ago
3 0

Answer:

All the answers are.

Explanation: 1 clouds and possible precipitation

2 each grid point on a three-dimensional get

3 it produces uneven heating of earths surface by the sun

4 C a warm surface current flows along the east coast of the United States and a cold water surface current flows along the West Coast of the United States

5 plate tectonics

6 wet soil absorbs heat more slowly, due to waters high heat capacity

7 top layer: exosphere, fourth layer:thermosphere, middle layer:mesosphere, second layer: stratosphere, lowest layer: troposphere

8 physics that describes how air moves and heat and moisture are exchanged.

I just took the test and these are the correct answers, I hope this helped you.

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The work done by an external force to move a -6.70 μc charge from point a to point b is 1.20×10−3 j .
ASHA 777 [7]

Answer:

108.7 V

Explanation:

Two forces are acting on the particle:

- The external force, whose work is W=1.20 \cdot 10^{-3}J

- The force of the electric field, whose work is equal to the change in electric potential energy of the charge: W_e=q\Delta V

where

q is the charge

\Delta V is the potential difference

The variation of kinetic energy of the charge is equal to the sum of the work done by the two forces:

K_f - K_i = W + W_e = W+q\Delta V

and since the charge starts from rest, K_i = 0, so the formula becomes

K_f = W+q\Delta V

In this problem, we have

W=1.20 \cdot 10^{-3}J is the work done by the external force

q=-6.70 \mu C=-6.7\cdot 10^{-6}C is the charge

K_f = 4.72\cdot 10^{-4}J is the final kinetic energy

Solving the formula for \Delta V, we find

\Delta V=\frac{K_f-W}{q}=\frac{4.72\cdot 10^{-4}J-1.2\cdot 10^{-3} J}{-6.7\cdot 10^{-6}C}=108.7 V

4 0
2 years ago
Read 2 more answers
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