Answer:
Its angular speed is 0.105 rad /s. The minute hand of a clock takes 60 minutes = 60 x 60 seconds to complete one rotation.
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Explanation:
Answer:
E.year₂ > E.year₁ (Second site is better)
Explanation:
Given data
![V_{1}=7 m/s\\Time_{1}=3000 hours/year\\V_{2}=10m/s\\Time_{2}=1500hours/year](https://tex.z-dn.net/?f=V_%7B1%7D%3D7%20m%2Fs%5C%5CTime_%7B1%7D%3D3000%20hours%2Fyear%5C%5CV_%7B2%7D%3D10m%2Fs%5C%5CTime_%7B2%7D%3D1500hours%2Fyear)
The power generation is the time rate of kinetic energy which can be calculated as:
Power=ΔKE=m×V²/2
Regarding that m ∝ V.Then
Power ∝ V³ ⇒ Power=constant×V³
Since ρa is constant for both sides and Area is the same as same wind turbine is used
For First site
![Power_{1}=const.V^3\\Power_{1}=const.(7m/s)^3\\Power_{1}=const.343Watt\\](https://tex.z-dn.net/?f=Power_%7B1%7D%3Dconst.V%5E3%5C%5CPower_%7B1%7D%3Dconst.%287m%2Fs%29%5E3%5C%5CPower_%7B1%7D%3Dconst.343Watt%5C%5C)
For second site
![Power_{2}=const.V_{2}^3\\Power_{2}=const.(10m/s)^3\\Power_{2}=const.1000W](https://tex.z-dn.net/?f=Power_%7B2%7D%3Dconst.V_%7B2%7D%5E3%5C%5CPower_%7B2%7D%3Dconst.%2810m%2Fs%29%5E3%5C%5CPower_%7B2%7D%3Dconst.1000W)
Calculating energy generation per year for each of two sites
E.year=Power×Operation time per year
For First site
E.year₁=Power₁×Operation time₁ per year
![E_{year1}=const.*343W*3000\\E_{year1}=const.1029000(W.hour/year)](https://tex.z-dn.net/?f=E_%7Byear1%7D%3Dconst.%2A343W%2A3000%5C%5CE_%7Byear1%7D%3Dconst.1029000%28W.hour%2Fyear%29)
For Second site
E.year₂=Power₂×Operation time₂ per year
![E_{year2}=const.*1000W*1500\\E_{year2}=const.1500000(W.hour/year)](https://tex.z-dn.net/?f=E_%7Byear2%7D%3Dconst.%2A1000W%2A1500%5C%5CE_%7Byear2%7D%3Dconst.1500000%28W.hour%2Fyear%29)
So
E.year₂ > E.year₁ (Second site is better)
Answer:
21.53 x 10^{6} N
Explanation:
force (F) = 4.71 x 10^{3} N
distance (s) = 4.57 km = 4570 m
how much work is done.
work = force x distance
work = 4.71 x 10^{3} x 4570 = 21.53 x 10^{6} N
Answer: g= 9,81 m/s^2 ( average value for g in the Earth)
Explanation: The value of g depend on the localization on the Earth for example at the poles g is equal to: 9.83 m/s^2
On the other hand, at the aquator g=9.78 m/s^2
Answer:
Law of conservation of energy.
<em>Hope it helps</em><em>.</em>