Answer:
Cat with 6 kg sitting on a 30 meter hill has greater potential energy.
Explanation:
gravitational potential energy (J) = mass (kg) × gravitational field × height (m)
<h3 /><h3><u>Note</u>:</h3>
gravitational field in Earth is 10 N/kg = <u>fixed unit</u>
<h3 /><h3><u>Given</u>:</h3>
1st Cat: 4 kg
2nd Cat: 6 kg
Both of their height is 30 meters.
<h3><u>Solve for g.p.e</u>:</h3>
1st cat = mgh = 4 × 10 × 30 = 1200 Joules
2nd cat = mgh = 6 × 10 × 30 = 1800 Joules
Answer:
force×distance
Explanation:
i think that's the answer and it could also be expressed as m×g×d
Answer:
Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Explanation:
Let a projectile is projected vertically upwards with a speed of u and reaches to the maximum height H.
At maximum height , the speed is zero and then the projective comes back on the ground.
Use the third equation of motion

Now let the velocity at the time of strike is v'.
Use third equation of motion, here initial velocity is zero.

Thus, the velocity at the time of strike is same as the velocity at the time of projection.
Answer:
To prevent from getting injured.