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garri49 [273]
3 years ago
8

What would the product look like if ROOR weren't used?

Chemistry
1 answer:
S_A_V [24]3 years ago
4 0

Answer:

The least substituted product (anti-Markovnikov)

Explanation:

The ROOR is used in the addition reaction of HBr to an organic substance (an alkene for example).

In normal conditions (with no ROOR) the adition of the halogen will be performed in the most substituted C (following the rule of Markovnikov that says that the stability increases with the more substituted is the C).

But in presence of ROOR, the reaction takes other mechanism (free radicals), and the product in this case is the one with the Br added in the least substituted C.

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18 g of argon occupy 750 ml at a particular temperature and pressure. How many grams of methane would occupy the same volume at
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Answer:

7.21 grams is the mass of methane

Explanation:

We may use the Ideal Gases Equation to solve this:

P. V = n. R. T

Let's determine the moles of Ar

18 g . 1 mol/ 39.9 g = 0.451 mol

In both situations, volume, temperature and pressure are the same so the moles of methane will also be the same as Argon's.

Let's convert the moles to mass of CH4.

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vredina [299]

Answer:

The answer is "152 pm".

Explanation:

The bond length from the values inside the atomic radii is calculated according to the query. This would be the upper limit of a molecule's binding length.

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\text{Bond length = Atomic radius of H + Atomic radius of Br}

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The method that can be used to separate the mixture is chromatography.

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To obtain the colors used, two solvents are mixed and the sample ink is dissolved in the solvents then spotted on a thin layer and put into a TLC chamber then the chromatogram is allowed to develop.

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Learn more about chromatography: brainly.com/question/26491567

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