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Anuta_ua [19.1K]
3 years ago
10

which of the answers below best describes the precaution you must make before connecting a capacitor to a circuit?

Physics
1 answer:
butalik [34]3 years ago
8 0

The characteristics of the capacitors can be found answer of which is the most important precaution before connecting a capacitor is:

  • Discharge the capacitor before handling

A capacitor in a computer that consists of metallic plates with an electrical charge in them, the main function of a capacitor is to store energy.

As a capacitor is an energy storage system, it has a charge Q on each plate, so it must be used with caution among the main measures we have.

  • Do not manipulate the capacitors after turning off a circuit, the energy is stored and you can receive a shock
  • Before connecting a capacitor, take the precaution of discharging it by short-circuiting its legs.

In conclusion with the characteristics of the capacitors we find that the answer is the most important precaution before connecting a capacitor is:

  • Discharge the capacitor before handling

Learn more about capacitors here:

brainly.com/question/14126841

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Two crates, one with mass 5.4 kg and the other with mass 8.2 kg, connected by a light rope. The coefficient of kinetic friction
Gnom [1K]

Answer:

R= 2.5 :ratio of the magnitude of the applied horizontal force to the magnitude of the tension in the rope connecting the blocks

Explanation:

We apply Newton's second law:

∑F=m*a

velocity  is constant ,then , a=0

Nomenclature

W: weight

m: mass

N : normal force

Ff: Friction force

μk: coefficient of kinetic friction

T: tension  force in the rope

F: applied horizontal force

g: acceleration due to gravity.

Force Calculation

W₁=m₁*g=5.4 kg *9.8m/s²=52.92 N

W₂=m₂*g=8.2 kg *9.8m/s²= 80.36N

∑Fy=0  

N₁-W₁=0 , N₁=W₁ = 52.92 N

N₂-W₂=0, N₂=W₂=80.36N

Ff₁= μk* N₁=0.4*52.92 N = 21.16N

Ff₂= μk* N₂=0.4*80.36N = 32.14N

Look at the attached graphic

Free-Body diagram m₁=5.4 kg

∑Fx=0

T- Ff₁=0 , T= Ff₁     ,    T= 21.16N

Free-Body diagram m₂=8.2 kg

∑Fx=0

F-T- Ff₂=0 , F=T+Ff₂= 21.16N+32.14N=53.3N

Ratio of the magnitude of the applied horizontal force to the magnitude of the tension in the rope connecting the blocks (R)

R= F/T= 53.3N/21.16N = 2.5

3 0
2 years ago
Two technicians are discussing an engine with an interference design. Technician A says if a valve remains open when its cylinde
maksim [4K]

Answer: Both Technician A and B are right.

Explanation:

Both Technicians are correct. when a valve remains open as it approaches the TDC(top dead center), they piston may strike the valve which would result to damage of the engine. Same applies when it is open as it approaches the top dead center as a valve train damage may occur. As the driven train is responsible for providing power to the wheels from the engine block.

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2 years ago
A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exert
Dimas [21]

A falling skydiver opens his parachute. A short time later, the weight of the skydiver-parachute system and the drag force exerted on the system are equal in magnitude. The following statements predicts the motion of the skydiver at this time

<u>The skydiver is moving downward with constant speed.</u>

Explanation:

Immediately on leaving the aircraft, the skydiver accelerates downwards due to the force of gravity. There is no air resistance acting in the upwards direction, and there is a resultant force acting downwards. The skydiver accelerates towards the ground.

The forces acting on a falling leaf are : gravity and air resistance.

The net force and the acceleration on the falling skydiver is upward.

An upward net force on a downward falling object would cause that object to slow down. The skydiver thus slows down.

As the speed decreases, the amount of air resistance also decreases until once more the skydiver reaches a terminal velocity.

<u>A skydiver falling at a constant speed opens his parachute. When the skydiver is falling, the forces are unbalanced.</u>

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lbvjy [14]

Answer:

a) solid sphere. Assuming no air resistance

Explanation:

If they all have the same mass and radius, the torque will be the same, but since their inertia is different, the angular acceleration will be different.

\tau = I*\alpha  =>   \alpha =\frac{\tau}{I}

So, the one with the biggest acceleration will be the one with the smallest inertia.

The inertia for each object, in ascending order are:

Solid Sphere = \frac{2}{5} *m*R^2=0.4*m*R^2

Solid Cylinder= \frac{1}{2} *m*R^2=0.5*m*R^2

Sphere Shell= \frac{2}{3} *m*R^2=0.67*m*R^2

Cylindrical Shell= m*R^2=m*R^2

As you can see, the solid sphere has the smallest inertia, and therefore, will have the greatest acceleration. (All of this assuming there is no air resistance)

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Robby skateboards 0.50 blocks to his friend's house in 1.2 minutes. What is his speed?
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The answer is 0.42 blocks per minute, Good Luck!
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