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Anuta_ua [19.1K]
3 years ago
10

which of the answers below best describes the precaution you must make before connecting a capacitor to a circuit?

Physics
1 answer:
butalik [34]3 years ago
8 0

The characteristics of the capacitors can be found answer of which is the most important precaution before connecting a capacitor is:

  • Discharge the capacitor before handling

A capacitor in a computer that consists of metallic plates with an electrical charge in them, the main function of a capacitor is to store energy.

As a capacitor is an energy storage system, it has a charge Q on each plate, so it must be used with caution among the main measures we have.

  • Do not manipulate the capacitors after turning off a circuit, the energy is stored and you can receive a shock
  • Before connecting a capacitor, take the precaution of discharging it by short-circuiting its legs.

In conclusion with the characteristics of the capacitors we find that the answer is the most important precaution before connecting a capacitor is:

  • Discharge the capacitor before handling

Learn more about capacitors here:

brainly.com/question/14126841

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Which describes the position on a horizontal number line
Savatey [412]

Answer:

It is formed by a horizontal number line, called the x-axis, and a vertical number line, called the y-axis.

Explanation:

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6 0
2 years ago
A rock is dropped from the top of a vertical cliff and takes 3.00 s to reach the ground below the cliff. A second rock is thrown
Trava [24]

Answer:

D) 12.3 m/s downward

Explanation:

We use the next free fall equation

h=v_{0}t+\frac{1}{2}gt^2

where h is the height of the cliff, v_{0} the initial velocity, g the acceleration of gravity (g=9.81m/s^2) and t is time.

For the fist rock v_{0}=0 since the rock was dropped, and t=3s, so we have:

h=(0m/s)(3s)+\frac{1}{2}(9.81m/s^2)(3s)^2

simplifying

h=44.145m

the height of the cliff is 44.145m

Now, about the second rock we know that is the same height and now the time es t=2s, and we need to find v_{0}

From the fist equation

h=v_{0}t+\frac{1}{2}gt^2

we clear for v_{0}

v_{0}t=h-\frac{1}{2} gt^2\\v_{0}=\frac{h}{t} -\frac{1}{2} gt

and substitute known values

v_{0}=\frac{44.145m}{2s} -\frac{1}{2} (9.81m/s^2)(2s)

v_{0}=22.07m/s -9.81m/s

v_{0}=12.26m/s wich rounds up to v_{0}=12.3m/s

the direction is downward because the rock is thrown so that it falls through the cliff.

7 0
3 years ago
Diane swim 5 kilometers against the current in the same amout of time it took her to swim 15 kilometers with the current . The r
lidiya [134]

Answer:

4 km/hr

Explanation:

suppose 's' is Diane's speed with no current.

't' represents time in hrs.

Using the formula:

Distance = speed 's' x time 't'

-> when she swims against the current, equation will be,

5= (s-2)t

t= 5/(s-2)

->when she was swimming with the current, equation is,

15= (s+2) t

t= 15/(s+2)

equating eq(1) and (2)

5/(s-2) = 15/(s+2)

5s + 10 = 15s - 30

40= 10s

s= 40/10

s=4

Therefore, if there were no current, her speed is 4km/hr

5 0
4 years ago
What average mechanical power (in W) must a 64.5 kg mountain climber generate to climb to the summit of a hill of height 285 m i
kakasveta [241]

Answer:61.275 W

Explanation:

Given

Mass of climber m=64.5 kg

Height to climb h=285 m

Time taken t=49 min \approx 2940 s

Now Using  Work-energy Theorem work done is given by

W=m g h

W=64.5\times 9.8 \times 285

W=180148.5 J

W=180.148 kJ

Now  Average Mechanical Power is given by

P=\frac{W}{\Delta t}

P=\frac{180.148}{2940}=0.0612 kW

P=61.275 W

7 0
3 years ago
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