Answer:
The number of atoms is ![N = 4.37*10^{22} \ atoms](https://tex.z-dn.net/?f=N%20%3D%204.37%2A10%5E%7B22%7D%20%5C%20atoms)
Explanation:
From the question we are told that
The mass of coin is ![m_n = 4.2g](https://tex.z-dn.net/?f=m_n%20%3D%204.2g)
Number of atom in one mole = ![n =6.02*10^{23} \ atoms](https://tex.z-dn.net/?f=n%20%3D6.02%2A10%5E%7B23%7D%20%5C%20atoms)
Molar mass of nickel ![M = 57.8g](https://tex.z-dn.net/?f=M%20%3D%2057.8g)
Now the relation to obtain the number of atom in the nickel coin is
![N = \frac{Mass \ of Nickel\ coin}{Molar \ mass\ of nickel } * No\ of\atoms \ in \ \ one\ mole\ of\ nickel](https://tex.z-dn.net/?f=N%20%3D%20%5Cfrac%7BMass%20%5C%20of%20Nickel%5C%20coin%7D%7BMolar%20%5C%20mass%5C%20of%20nickel%20%7D%20%20%2A%20No%5C%20of%5Catoms%20%5C%20in%20%5C%20%5C%20one%5C%20%20mole%5C%20of%5C%20nickel)
![= \frac{4.2}{57.8}* 6.02*10^{23}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7B4.2%7D%7B57.8%7D%2A%206.02%2A10%5E%7B23%7D)
![=4.37 *10^{22} atoms](https://tex.z-dn.net/?f=%3D4.37%20%2A10%5E%7B22%7D%20atoms)
Answer: A:The reproductive system produces hormones.
B:The reproductive system transports reproductive cells.
C:The reproductive system produces reproductive cells.
Explanation:
A:The reproductive system produces hormones. : The reproductive organs ovaries in females and testes in males produces hormones. The ovaries produce estrogen and progesterone and testes produce testosterone.
B:The reproductive system transports reproductive cells. : The ovaries in females transfers an egg into the fallopian tube and testes in males secrete sperms at the time of copulation the fertilization of egg and sperm leads to the development of zygote the precursor of new life.
C:The reproductive system produces reproductive cells.: The ovaries undergo oogenesis and in testes spermatogenesis takes place to develop egg and sperms respectively.
Answer:
The height of the cliff is, h = 78.4 m
Explanation:
Given,
The horizontal velocity of the projectile, Vx = 20 m/s
The range of the projectile, s = 80 m
The projectile projected from a height is given by the formula
<em> S = Vx [Vy + √(Vy² + 2gh)] / g
</em>
Therefore,
h = S²g/2Vx²
Substituting the values
h = 80² x 9.8/ (2 x 20²)
= 78.4 m
Hence, the height of the cliff is, h = 78.4 m