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Nikolay [14]
3 years ago
15

In the graph above for the dissociation of a strong acid, why do the bars for H3O+ and A- have the same height as the bar for HA

?

Chemistry
1 answer:
dimaraw [331]3 years ago
6 0

Answer:

The concentration of HA is the same as concentration of H3O+ and A- produced.

Explanation:

The dissociation equation is given below:

HA(aq) + H2O (l) —> H3O+(aq) + A-(aq)

From the reaction above, we can see that the acid is monoprotic acid i.e it has only 1 ionisable hydrogen atom.

Now, from the balanced equation, we can see that the acid produced equal concentration of H3O+ and A-.

This account for the reason why the bars for H3O+ and A- have the same height as the bar for HA.

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A 3.06 gram sample of an unknown hydrocarbon with empirical formula CH2O was found to contain 0.0170 moles of the substance. Wha
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Answer:

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Explanation:

Step 1: Determine the molecular mass of the compound

The sample has a mass (m) of 3.06 g and it contains (n) 0.0170 moles. The molar mass M is:

M = m/n = 3.06/0.0170 mol = 180 g/mol

Then, the molecular mass is 180 amu.

Step 2: Determine the molar mass of the empirical formula.

M(CH₂O) = 1 × M(C) + 2 × M(H) + 1 × M(O)

M(CH₂O) = 1 × 12 g/mol + 2 × 1 g/mol + 1 × 16 g/mol = 30 g/mol

Step 3: Determine the molecular formula

First, we will determine "n" according to the following expression.

n = molar mass molecular formula / molar mass empirical formula

n = 180 g/mol / 30 g/mol = 6

The molecular formula is:

n × CH₂O = 6 × CH₂O = C₆H₁₂O₆

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During a chemical reaction, two hydrogen atoms combine with two oxygen atoms. How many hydrogen and oxygen atoms will be present
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What is the molarity of a solution made from 325.4 g of AlCl3 (MM 133.34 g/mol) to make 500.0 mL?
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Answer : The molarity of a solution is, 4.88 M

Explanation : Given,

Mass of AlCl_3 = 325.4 g

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Molarity : It is defined as the number of moles of solute present in one liter of volume of solution.

Formula used :

\text{Molarity}=\frac{\text{Mass of }AlCl_3\times 1000}{\text{Molar mass of }AlCl_3\times \text{Volume of solution (in mL)}}

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Therefore, the molarity of a solution is, 4.88 M

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